2 mole of `N_2H_4` loses 16 mole of electron is beings converted to a new compound X. Assuming that all of the N appears in the new compound. What is the oxidation state of 'N' in X ?

2 mole of N_(2)H_(4) loses 16 mole of electron is being converted to a new compound X . Assuming that all of the N appears in the new compound. What is the oxidation state of 'N' in X ?

One mole of N_(2)H_(4) loses ten moles of electrons to form a new compound A . Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in A ? (There is no change in the oxidation state of hydrogen.)

One mole of N_(2)H_(4) loses ten moles of electrons of form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? (There is no change in the oxidation state of hydrogen.)

Oxidation Number of N in N_2H_5^+

How many electrons should X_(2)H_(4) liberate so that in the new compound X shows oxidation number of -1//2 (E.N. X gt H)

How many electrons should X_(2)H_(4) liberate so that in the new compound X shows oxidation number of -1//2 (E.N. X gt H)

One mole of hydrazine loses 10 moles of electrons. If all the hydrogen content is present in the product, the oxidation number of nitrogen in product is +x. What is value of x.

The correct order of N-compounds in its decreasing order of oxidation states is

What is the valency of N in following compounds. N_2O_5

What is the valency of N in following compounds. N_2O_3