`0.1g` of a solution containing `Na_2 CO_3 and NaHCO_3` requires `10mL` of `0.01 N HCI` for neutralization using phenolphthalein as an indicator. mass % of `Na_2 CO_3` in solution is :

0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is:

30 " mL of " a solution of mixture of Na_2CO_3 and NaHCO_3 required 12 " mL of " 0.05 M H_2SO_4 using phenolphthalein as indicator. With methyl orange 30 " mL of " the same solution required 40 " mL of " same H_2SO_4 . Calculate the amount of Na_2CO_3 and NaHCO_3 per litre in the mnixture.

1.7225 g of a metal (bivalent) salt A_(x)(CO_3)_(y)(OH)_(z) was dissolved in water to make 100 " mL of " solution 50 " mL of " this solution required 10 " mL of " 0.5 M H_2SO_4 solution for complete neutralisation using phenolphthalein indicator. Another 50 mL solution required 15 " mL of " same acid using methyl orange indicator. Deduce the formula of the salt.

0.5 g of a mixture of K_2CO_3 and Li_2CO_3 requires 30 " mL of " 0.25 N Hci for neutralisaion. Calculate the percentage composition of the mixture.

In the study of titration of NaOH and Na_(2)CO_(3) . NaOH and NaHCO_(3) , Na_(2)CO_(3) and NaHCO_(3) , phenophthalein and methyl orange are used as indicators. (a). When phenolphthalein is used as an indicator for the above mixture: (i). It indicates complete neutralisation of NaOH or KOH (ii). It indicates half neutralisation of Na_(2)CO_(3) because NaHCO_(3) is formed at the end point. (b). When methyl orange is used as an indicator for the above mixture (i). It indicates complete neutralisation of NaOH or KOH (ii). It indicates half neutralisation of Na_(2)CO_(3) because NaCl is formed at the end point. Q. A 10 g moxture of NaHCO_(3) and KOH is dissolved in water to make 1000 mL solution. 100 " mL of " this solution required 50 " mL of " 0.2 M HCl for complete neutralisation in the presence of phenolphthalein as indicator What is the percentage of NaHCO_(3) in the mixture?

The overall equation for the reaction between sodium carbonate solution and dilute hydrochloric acid is Na_(2)CO_(3)(aq.)+2HCl(aq.)rarrNaCl(aq)+CO_(2)(g)H_(2)O(l) If you had the two solutions of the same concentration, you would have to use double volume of HCl to reach the equivalence point. Indicators change their colours at the end point of the reaction and hence we are able to know the end points (equivalence points of reactions). 25 ml of Na_(2)CO_(3) solution requires 100 ml of 0.1 M HCl to reach end point with phenolphthalein indicator. Molarity of HCO_(3^(-)) ions in the resulting solution is

The solution of Na_2CO_3 has PH

A mixutre solution of KOH and Na_2CO_3 requires 15 " mL of " (N)/(20) HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH present in the solution.

20mL of 0.1M solution of compound Na_2CO_3 .NaHCO_3. 2H_2O is titrated against 0.05 M HCI . x mL of HCI is used when phenolphthalein is used as an indicator and y mL of HCI is used when methly orange is the indicator in two separate titrations. Hence (y-x) is :