A mixture `NaOH+Na_(2)CO_(3)` required 25mL of 0.1 M HCl using phenolpththalein as the indicator. However, the same amount of the mixture required 30mL of 0.1M HCl when methyl orange was used as the indicator. The molar ration of `NaOH and Na_(2)CO_(3)` in the mixture was:

A sample of NaHCO_(3) + Na_(2)CO_(3) required 20 ml of HCl using phenolphthalein as indicator and 35ml more required if methyl orange is used as indicator . Then molar ratio of NaHCO_(3) to Na_(2)CO_(3) is

In the study of titration of NaOH and Na_(2)CO_(3) . NaOH and NaHCO_(3) , Na_(2)CO_(3) and NaHCO_(3) , phenophthalein and methyl orange are used as indicators. (a). When phenolphthalein is used as an indicator for the above mixture: (i). It indicates complete neutralisation of NaOH or KOH (ii). It indicates half neutralisation of Na_(2)CO_(3) because NaHCO_(3) is formed at the end point. (b). When methyl orange is used as an indicator for the above mixture (i). It indicates complete neutralisation of NaOH or KOH (ii). It indicates half neutralisation of Na_(2)CO_(3) because NaCl is formed at the end point. Q. 1 L solution of Na_(2)CO_(3) and NaOH was made in H_(2)O . 100 " mL of " this solution required 20 " mL of " 0.4 M HCl in the presence of phenolphthalein however, another 100 mL sample of the same solution required 25 " mL of " the same acid in the presence of methyl orange as indicator. What is the molar ratio of Na_(2)CO_(3) and NaOH in the original mixture.

30 " mL of " a solution of mixture of Na_2CO_3 and NaHCO_3 required 12 " mL of " 0.05 M H_2SO_4 using phenolphthalein as indicator. With methyl orange 30 " mL of " the same solution required 40 " mL of " same H_2SO_4 . Calculate the amount of Na_2CO_3 and NaHCO_3 per litre in the mnixture.

200 " mL of " a solution of a mixture of NaOH and Na_2CO_3 was first titrated with 0.1 M HCl using phenolphthalein indicator. 17.5 " mL of " HCl was required for the same HCl was again required for next end point. Find the amount of NaOH and Na_2CO_3 in the mixture.

A mixutre solution of KOH and Na_2CO_3 requires 15 " mL of " (N)/(20) HCl when titrated with phenolphthalein as indicator.But the same amoound of the solutions when titrated with methyl orange as indicator requires 25 " mL of " the same acid. Calculate the amount of KOH present in the solution.

The best indicator for titrating 0.1 N Na_2CO_3 against 0.1 N HCl is

A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is:

0.58 g of CH_3(CH_2)_(c)COOH was burnt in excess air and the resulting gases (CO_2 and H_2O ) were passed through excess NaOH solution. The resulting solution was divided into two equal parts. One part requires 50 " mL of " 1.0 M HCl for complete neutralisation using phenolphthalein indicator. Another part required 80 " mL of " same HCl for neutralisation using methyl orange as indicator. Calculate the value of n and the amount of excess NaOH solution taken initially.

Given two mixtures: (I) NaOH and Na_(2)CO_(3) and (II) NaHCO_(3) and Na_(2)CO_(3) . 100 ml of mixture I required w and x ml of 1 M HCl is separate titrations using phenophthalein and methyl orange indicators while 100 ml of mixture II required y and z ml of same HCl solutioni in separate titrations using the same indicators.

If amixture of Na_(2)CO_(3) and NaOH in equimolar quantities when reacts with 0.1 M HCl in presence of phenolphthalein indicator consumes 30 ml of the acid. What will be the volume (in mL) of 0.15 M H_(2)SO_(4) used in the separate titration of same mixture in presence of methyl orange indicator.