`10L` of hard water required `5.6g` of lime for removing haardness. Hence temporary hardness in ppm of `CaCO_3` is :

10L of hard water required 5.6g of lime for removing hardness. Hence temperorary hardness in ppm of CaCO_(3) is:

10 L of hard water required 0.56 g of lime (CaO) for removing hardness. Hence, temporary hardness in ppm (part per million 10^(6) ) of CaCO_(3) is:

10 L of hard water requires 0.28 g of lime (CaO) for removing hardness. Calculate the temporary hardness in ppm of CaCO_(3) .

10 L of hard water requires 0.28 g of line (CaO) for removing hardness. Calculate the temporary hardness in ppm of CaCO_(3) .

How can we remove hardness in temporary hard water?

Only temporary hardness of water is removed by

Washing soda ( Na_2CO_(3).10H_2O ) is widely used in softening of hard water. If 1L of hard water requires 0.0143g of washing soda, what is hardness of water in terms of p p m of CaCO_3 ?

Which one of the following removes temporary hardness of water ?

The method used to remove temporary hardness of water is:

One litre of a sample of hard water contains 5.55 mg of CaCl_(2) and 4.75 mg of MgCl_(2) . The total hardness of ppm of CaCO_(3) is