To a `10mL, 1M` aqueous solution of `Br_2,` excess of `NaOH` is added so that all `Br_2` is disproportionated to `Br^- and BrO_3^-`. The resulting solution is free from `Br^-`, by extraction and excess of `OH^-` neutralised by acidifying the solution. The resulting solution is sufficient to react with `2g` of impure `Ca C_2 O_4 (M=128 g/mol)` sample. The % purity of oxalate sample is :

To a 10mL, 1M aqueous solution of Br_(2) , excess of NaOH is added so that all Br_(2) is disproportionated to Br^(-) and BrO_(3)^(-) . The resulting solution is free from Br^(-) , by extraction and excess of OH^(-) neutralised by acidifying the solution. The resulting solution is suffcient to react with 2 g of impure CaC_(2)O_(4) (M= 128g/mol) sample. The % purity of oxalate sample is :

10 mL of 1.0 M aqueous solution of Br_(2) is added to excess of NaOH in order to disproportionate quantitatively to Br^(-) " and " BrO_(3)^(-) . The resulting soluting is made free from Br^(-) ion by extraction and excess of OH^(-) neutralized by acidifying the solution. This solution requires 1.5 g of an impure CaC_(2)O_(4) sample for complete redox change . Calculate % purity of CaC_(2)O_(4) sample.

100ml of 0.2 M H_(2)SO_(4) is added to 100 ml of 0.2 M NaOH . The resulting solution will be

If 100 mL of 1 N H_(2)SO_(4) is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

50 mL of H_(2)O is added to 50 mL of 1 xx 10^(-3)M barium hydroxide solution. What is the pH of the resulting solution?

When 2.5g of a sample of mohr's salt reacts completely with 50mL of N/10 KMnO_4 solution. The % purity of the sample of Mohr's salt is :

A sample of Na_(2)CO_(3).H_(2)O weighing 0.62 g is added to 10 ml of 0.1 N H_(2)SO_(4) solution . The resulting solution will be

20 ml of 0.4 M H_(2)SO_(4) , and 80 ml of 0.2 M NaOH are mixed. Then the p^(H) of the resulting solution is

The resulting solution obtained by mixing 100ml, 0.1M H_2SO_4 and 50ml ,0.4M NaOH will be

When 0.2M solution of acetic acid is neutralised with 0.2M NaOH in 500 mL of water, the pH of the resulting solution will be: [pK_(a) of acetic acid = 4.74]