A `50mL` of solution of `I_2` is divided into two unequal parts. I part with hypo solution in acidic medium. 15mL of `0.4M` hypo was consumed. II part was added with 100mL of `0.3M NaOH` solution. Residual base required to mL of `0.3M H_2SO_4` solution for complete neutralization. What was the initial concentration of `I_2?`

A 150 mL of solution of I_(2) is divided into two unequal parts. I part reacts with hypo solution solution in acidic medium. 15 mL of 0.4 M hypo was consumed. II part was added with 100 mL of 0.3 M NaOH solution. Residual base required 10 mL 0.3 M H_2SO_4 solution for complete neutralization. What was the initial concentration of I_(2) ?

Volume of 0.1 M H_2SO_4 solution required to neutralize 50 ml of 0.1 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 20 ml of 0.2 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 40 ml of 0.2 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 30 ml of 0.1 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 20 ml of 0.1 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 60 ml of 0.1 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 40 ml of 0.1 M NaOH solution is :

Volume of 0.1 M H_2SO_4 solution required to neutralize 70 ml of 0.1 M NaOH solution is :

10mL of 2(M) NaOH solution is added to 200mL of 0.5 (M) of NaOH solution. What is the final concentration?