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When ethyl acetate was was hydrolysedin ...

When ethyl acetate was was hydrolysedin presemce of 0.1 M HCl, the rate constant was found to be `5.4xx10^(-5)s^(-1)`. But in presence of 0.1 M `H_(2)SO_(4)` the rate constant was found to be `6.25xx10^(-5)s^(-1)`. Thus it may be concluded that:

A

`H_(2)SO_(4)` furnishes more `H^(+)` than HCl

B

`H_(2)SO_(4)` furnishes less `H^(+)` than HCl

C

both have the same strength

D

will depend on concentration of ethyl acetate

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the hydrolysis of ethyl acetate in the presence of two different acids: HCl and H2SO4. We are given the rate constants for both reactions and need to conclude which acid furnishes more H⁺ ions during the reaction. ### Step-by-Step Solution: 1. **Identify Given Data:** - Rate constant for HCl (K₁) = 5.4 x 10⁻⁵ s⁻¹ - Rate constant for H₂SO₄ (K₂) = 6.25 x 10⁻⁵ s⁻¹ - Concentration of both acids = 0.1 M 2. **Understand the Rate Law:** The rate of a reaction can be expressed as: \[ \text{Rate} = k \cdot [\text{Reactant}]^n \] where \( k \) is the rate constant, \([\text{Reactant}]\) is the concentration of the reactant, and \( n \) is the order of the reaction. 3. **Set Up Rate Expressions:** For HCl: \[ \text{Rate}_{\text{HCl}} = K_1 \cdot [\text{Ethyl Acetate}]^n = 5.4 \times 10^{-5} \cdot (0.1)^n \] For H₂SO₄: \[ \text{Rate}_{\text{H₂SO₄}} = K_2 \cdot [\text{Ethyl Acetate}]^n = 6.25 \times 10^{-5} \cdot (0.1)^n \] 4. **Compare Rates:** Since the concentration of ethyl acetate and the order of the reaction (n) are the same for both reactions, we can compare the rate constants directly: \[ \text{Rate}_{\text{H₂SO₄}} > \text{Rate}_{\text{HCl}} \] This implies: \[ 6.25 \times 10^{-5} > 5.4 \times 10^{-5} \] 5. **Conclusion:** Since the rate of hydrolysis is greater in the presence of H₂SO₄ than in the presence of HCl, we can conclude that H₂SO₄ furnishes more H⁺ ions than HCl. This is because the increase in the rate of reaction is attributed to the higher availability of H⁺ ions from H₂SO₄. ### Final Answer: The correct conclusion is that **H₂SO₄ furnishes more H⁺ ions than HCl.** ---
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