`_(1)^(1)H` is a stable isotope . `_(1)^(3)H` is expected to disintegrated by :

Options

A. `alpha`-emission
B. `beta`-emission
C. Positron emission
D. proton emission

Answer

To solve the question regarding the disintegration of the isotope tritium (₁³H), we will analyze the decay process step by step.

### Step-by-Step Solution:

1. **Identify the Isotope**:
Tritium (₁³H) is a hydrogen isotope with one proton and two neutrons in its nucleus. It is radioactive and undergoes decay.

2. **Understand the Decay Process**:
Tritium is expected to disintegrate through a process known as beta decay. In beta decay, a neutron in the nucleus is transformed into a proton, and a beta particle (which is an electron) is emitted.

3. **Write the Decay Equation**:
The decay of tritium can be represented as follows:
\[ _{1}^{3}H \rightarrow _{1}^{2}H + \beta^{-} + \bar{\nu} \]
Here, _{1}^{2}H represents deuterium (another isotope of hydrogen), β⁻ is the emitted beta particle (electron), and \(\bar{\nu}\) is the antineutrino.

4. **Conclusion**:
Therefore, tritium (₁³H) disintegrates primarily by beta emission, converting into deuterium (₁²H) and releasing a beta particle.

### Final Answer:
Tritium (₁³H) is expected to disintegrate by **beta emission**.

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