`X rarr _(82)^(206)Pb+_(2)^(4)He` .In this reaction predict the position of group of X:

Options

A. II B
B. IV B
C. VI A
D. VI B

Answer

To solve the question, we need to analyze the nuclear reaction provided and determine the position of element X in the periodic table.

### Step-by-Step Solution:

1. **Identify the Reaction**: The reaction given is:
\[ X \rightarrow _{82}^{206}Pb + _{2}^{4}He \]
This indicates that element X decays into lead (Pb) and helium (He).

2. **Determine Atomic Numbers**:
- The atomic number of lead (Pb) is 82.
- The atomic number of helium (He) is 2.

3. **Calculate the Total Atomic Number**:
To find the atomic number of element X, we add the atomic numbers of the products:
\[ \text{Atomic Number of X} = 82 + 2 = 84 \]

4. **Determine Mass Numbers**:
- The mass number of lead (Pb) is 206.
- The mass number of helium (He) is 4.

5. **Calculate the Total Mass Number**:
To find the mass number of element X, we add the mass numbers of the products:
\[ \text{Mass Number of X} = 206 + 4 = 210 \]

6. **Identify Element X**:
The element with atomic number 84 is Polonium (Po). Therefore, X is polonium with:
- Atomic Number: 84
- Mass Number: 210

7. **Determine the Group of Polonium**:
Polonium is located in Group 16 of the periodic table, which is also referred to as Group 6A.

8. **Conclusion**:
Based on the analysis, the position of group of X (Polonium) is:
\[ \text{Group 6A (or Group 16)} \]

### Final Answer:
The correct option for the given question is **6A**.

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