A sample of raw material contain `NaNO_(3)`. It contains some `NaIO_(3)` also. The `NaIO_(3)` can be used as a source of iodine, produced in the following reactions:
`IO_(3)^(-)+HSO_(3)^(-) to I^(-)+SO_(4)^(-)`...................(1)
`I^(-)+IO_(3)^(-) to I_(2)+H_(2)O`............(2)
One litre of sample solution containing 396 g `NaIO_(3)` is treated with stoichiometric quantity of `NaHSO_(3)`. Now a substantial amount of solution is added to reaction mixture to bring about the reaction (2).

IO_(3)^(-)+I^(-)+H^(+) to

Chile salt peter a source of NaNO_(3) also contains NaIO_(3) the NaIO_(3) is a source of I_(2) produced as shown in the following equation: Step I: IO_(3)^(ɵ)+3HSO_(3)^(ɵ)+3SO_(4)^(2-) Step II: 5I^(ɵ)+IO_(3)^(ɵ)+6H^(o+)to3I_(2)(s)+3H_(2)O One litre sample of chile salt peter solution containing 6.6 g NaIO_(3) is treated with NaHSO_(3) Now an additional amount of same solution is added to the reaction mixture to bring about the second titration. Calculate the weight of NaHSO_(3) requried in step I and what additional volume of chile salt peter mist be added in step II to bring out complete conversion of I^(ɵ) to I_(2) .

Balance the following equation in basic medium. Cr(OH)_(3)+IO_(3)^(-)toCrO_(4)^(2-)+I^(-)

Complete the following reactions: (i) C_(2) H_(4) + O_(2) to (ii) 4Al + 3 O_(2) to

Complete and balance the following reactions: CIO_(3)^(Theta)+I^(Theta)+H_(2)SO_(4)^(Theta)rarr CI^(Theta)+HSO_(4)^(Theta)+…….

One litre of a solution contains 15.12 g of HNO_(3) and one litre of another solution contains 3.2 g of NaOH. In what volume ratio must these solutions be mixed to obtain a neutral solution ?

An queous solution containing 2.14 g KIO_3 was treated with 100 ml of 0.4 M Kl solution, the weight of I_2 produced is-

Balance the following half-reactions in acidic medium: (a) IO_(3)^(Ө)(aq) rarr I_(3)^(Ө)(aq)

The nitrogen containing compound produced in the reaction of NH_(3) with O_(2) is

Draw structure NaIO_(3)