Calculate the total moles of atoms of each element present in 122.5 g of `KC LO_(3)`

Answer

To calculate the total moles of atoms of each element present in 122.5 g of KClO3 (potassium chlorate), follow these steps:

### Step 1: Calculate the number of moles of KClO3
To find the number of moles, use the formula:

\[ \text{Number of moles} = \frac{\text{Given weight}}{\text{Molecular weight}} \]

Given:
- Weight of KClO3 = 122.5 g
- Molecular weight of KClO3 = 122.5 g/mol

Substituting the values:

\[ \text{Number of moles of KClO3} = \frac{122.5 \, \text{g}}{122.5 \, \text{g/mol}} = 1 \, \text{mole} \]

### Step 2: Determine the total number of atoms in KClO3
Next, identify the number of atoms in one formula unit of KClO3. The composition is as follows:
- 1 potassium (K) atom
- 1 chlorine (Cl) atom
- 3 oxygen (O) atoms

Adding these together gives:

\[ \text{Total number of atoms} = 1 + 1 + 3 = 5 \, \text{atoms} \]

### Step 3: Calculate the total moles of atoms
Now, multiply the number of moles of KClO3 by the total number of atoms per formula unit:

\[ \text{Total moles of atoms} = \text{Number of moles of KClO3} \times \text{Total number of atoms} \]

Substituting the values:

\[ \text{Total moles of atoms} = 1 \, \text{mole} \times 5 \, \text{atoms} = 5 \, \text{moles} \]

### Final Answer
The total moles of atoms of each element present in 122.5 g of KClO3 is **5 moles**.

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