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A crystal is made of particles X and Y...

A crystal is made of particles X and Y.X form fcc packing and Y occupies all the octahedral voids . If all the particles along one body diagonal are removed then the formula of the crystal would de :

A

`X_(4)Y_(3)`

B

`X_(5)Y_(5)`

C

`X_(5)Y_(4)`

D

None of these

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The correct Answer is:
To solve the problem, we need to follow these steps: ### Step 1: Understand the structure of the crystal The crystal is made up of two types of particles: X and Y. The X particles form a face-centered cubic (FCC) lattice, and the Y particles occupy all the octahedral voids in this structure. ### Step 2: Determine the number of X particles in the FCC lattice In an FCC lattice: - There are 8 corner atoms, each contributing \( \frac{1}{8} \) to the unit cell. - There are 6 face-centered atoms, each contributing \( 1 \) to the unit cell. Calculating the total contribution of X particles: - Contribution from corner atoms: \( 8 \times \frac{1}{8} = 1 \) - Contribution from face-centered atoms: \( 6 \times 1 = 6 \) Total number of X particles in the unit cell: \[ \text{Total X} = 1 + 6 = 7 \] ### Step 3: Determine the number of Y particles in the octahedral voids In an FCC lattice, the octahedral voids are located: - 1 at the body center (contributes 1) - 12 at the edge centers, each contributing \( \frac{1}{4} \) Calculating the total contribution of Y particles: - Contribution from body center: \( 1 \) - Contribution from edge centers: \( 12 \times \frac{1}{4} = 3 \) Total number of Y particles in the unit cell: \[ \text{Total Y} = 1 + 3 = 4 \] ### Step 4: Removing particles along one body diagonal When we remove the particles along one body diagonal, we are removing: - 2 X particles from the corners (each corner contributes \( \frac{1}{8} \)) - 1 Y particle from the body center ### Step 5: Calculate the effective number of X and Y particles after removal After removing the particles: - Remaining X particles: - Original: 7 - Removed: 2 - Remaining: \( 7 - 2 = 5 \) - Remaining Y particles: - Original: 4 - Removed: 1 - Remaining: \( 4 - 1 = 3 \) ### Step 6: Determine the effective number of particles Now we need to express the remaining particles in terms of effective contributions: - For X: - 5 X particles remain. - For Y: - 3 Y particles remain. ### Step 7: Write the formula of the crystal The ratio of X to Y is: \[ \text{Ratio} = \frac{5}{3} \] To express this in a whole number ratio, we can multiply by 4 to avoid fractions: - X: \( 5 \times 4 = 20 \) - Y: \( 3 \times 4 = 12 \) Thus, the formula of the crystal becomes: \[ \text{Formula} = X_5Y_4 \] ### Final Answer The formula of the crystal is \( X_5Y_4 \). ---
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