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For any H like system, the ratio of velo...

For any H like system, the ratio of velocities of electron in I, II & III orbit i.e.,`V_(1):V_(2):V_(3)` will be:

A

(a) `1:2:3`

B

(b) `1:1/2:1/3`

C

(c) `3:2:1`

D

(d) `1:1:1`

Text Solution

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To find the ratio of the velocities of the electron in the first, second, and third orbits (V1:V2:V3) for any hydrogen-like system, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: The velocity of an electron in a hydrogen-like atom is given by the formula: \[ V_n \propto \frac{Z}{n} \] where \( V_n \) is the velocity in the nth orbit, \( Z \) is the atomic number, and \( n \) is the principal quantum number (the orbit number). 2. **Identifying the Atomic Number**: For hydrogen-like systems, the atomic number \( Z \) is constant for a given atom. Therefore, we can focus on the relationship between the velocities and the orbit numbers. 3. **Setting Up the Ratios**: Since \( V_n \propto \frac{Z}{n} \), we can express the velocities for the first, second, and third orbits as: \[ V_1 \propto \frac{Z}{1}, \quad V_2 \propto \frac{Z}{2}, \quad V_3 \propto \frac{Z}{3} \] 4. **Forming the Velocity Ratio**: The ratio of the velocities \( V_1 : V_2 : V_3 \) can be expressed as: \[ V_1 : V_2 : V_3 = \frac{Z}{1} : \frac{Z}{2} : \frac{Z}{3} \] Since \( Z \) is common in all terms, it cancels out: \[ V_1 : V_2 : V_3 = 1 : \frac{1}{2} : \frac{1}{3} \] 5. **Finding a Common Denominator**: To simplify this ratio, we can convert it to a common denominator: \[ 1 : \frac{1}{2} : \frac{1}{3} = 6 : 3 : 2 \] 6. **Final Ratio**: Thus, the final ratio of velocities of the electron in the first, second, and third orbits is: \[ V_1 : V_2 : V_3 = 6 : 3 : 2 \] ### Conclusion: The ratio of the velocities of the electron in the first, second, and third orbits of a hydrogen-like system is \( 6 : 3 : 2 \).
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