A dye absorbs a photon of wavelength `lambda` and re`-` emits the same energy into two phorons of wavelengths `lambda_(1)` and `lambda_(2)` respectively. The wavelength `lambda` is related with `lambda_(1)` and `lambda_(2)` as `:`
NARENDRA AWASTHI ENGLISH|Exercise Match the column|1 Videos
Similar Questions
Explore conceptually related problems
The energy of a photon of wavelength lambda is
Momentum of a photon of wavelength lambda is :
The mass of photon of wavelength lambda is given by
If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then
If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then
Let K_(1) be the maximum kinetic energy of photoelectrons emitted by a light of wavelength lambda_(1) and K_(2) corresponding to lambda_( 2). If lambda_(1) = 2lambda_(2) , then
Two sound waves of wavelengths lambda_(1) and lambda_(2) (lambda _(2) gt lambda_(1)) produces n beats//s , the speed of sound is
Bichromatic light of wavelengths lambda_1= 5000Å and lambda_2=7000Å are used in YDSE. Then,
The wavelengths of photons emitted by electron transition between two similar leveis in H and He^(+) are lambda_(1) and lambda_(2) respectively. Then :-
The wavelengths of photons emitted by electron transition between two similar leveis in H and He^(+) are lambda_(1) and lambda_(2) respectively. Then :-