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The correct Schrodinger's wave equation ...

The correct Schrodinger's wave equation for a electron with total energy E and potential energy V is given by:

A

`(del^(2)Psi)/(delx^(2))+(del^(2)Psi)/(dely^(2))+(del^(2)Psi)/(delz^(2))+(8pi^(2))/(mh^(2))(E-V)Psi=0`

B

`(del^(2)Psi)/(delx^(2))+(del^(2)Psi)/(dely^(2))+(del^(2)Psi)/(delz^(2))+(8pim)/(h^(2))(E-V)Psi=0`

C

`(del^(2)Psi)/(delx^(2))+(del^(2)Psi)/(dely^(2))+(del^(2)Psi)/(delz^(2))+(8pi^(2)m)/(h^(2))(E-V)Psi=0`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To derive the correct Schrödinger wave equation for an electron with total energy \( E \) and potential energy \( V \), we can follow these steps: ### Step 1: Understand the Schrödinger Wave Equation The Schrödinger wave equation is a fundamental equation in quantum mechanics that describes how the quantum state of a physical system changes over time. It is expressed in terms of the wave function \( \psi \). ### Step 2: Write the Time-Independent Schrödinger Equation For a particle in a potential \( V \), the time-independent Schrödinger equation can be written as: \[ -\frac{\hbar^2}{2m} \nabla^2 \psi + V \psi = E \psi \] where: - \( \hbar \) is the reduced Planck's constant, - \( m \) is the mass of the electron, - \( \nabla^2 \) is the Laplacian operator, which in three dimensions is given by: \[ \nabla^2 = \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2} + \frac{\partial^2}{\partial z^2} \] ### Step 3: Rearranging the Equation Rearranging the equation gives: \[ -\frac{\hbar^2}{2m} \nabla^2 \psi = (E - V) \psi \] ### Step 4: Multiply by \(-\frac{2m}{\hbar^2}\) To express the equation in a standard form, we can multiply both sides by \(-\frac{2m}{\hbar^2}\): \[ \nabla^2 \psi + \frac{2m}{\hbar^2} (V - E) \psi = 0 \] ### Step 5: Substitute \( \hbar \) with \( h \) Since \( \hbar = \frac{h}{2\pi} \), we can express the equation in terms of \( h \): \[ \nabla^2 \psi + \frac{8\pi^2 m}{h^2} (V - E) \psi = 0 \] ### Step 6: Final Form of the Schrödinger Wave Equation Thus, the final form of the Schrödinger wave equation for an electron with total energy \( E \) and potential energy \( V \) is: \[ \nabla^2 \psi + \frac{8\pi^2 m}{h^2} (V - E) \psi = 0 \] ### Conclusion The correct Schrödinger wave equation is: \[ \frac{\partial^2 \psi}{\partial x^2} + \frac{\partial^2 \psi}{\partial y^2} + \frac{\partial^2 \psi}{\partial z^2} + \frac{8\pi^2 m}{h^2} (V - E) \psi = 0 \] The correct option that expresses this equation is option C. ---
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