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The electronic structure of four elements A,B, C, D are (a) 1s^(2) (b) 1s^(2), 2s^(2), 2p^(2) ( c) 1s^(2), 2s^(2), 2p^(5) (d) 1s^(2), 2s^(2) 2p^(6) The tendency to form electrovalent bond is largest in
The number of unpaired electrons in 1s^(2) 2s^(2) 2p^(3) is
Number of unpaired electrons in the electronic configuration 1s^(2)2s^(2)2p^(4) is
The element with configuration 1s^(2) 2s^(2) 2p^(6) 3s^(2) would be
The element whose electronic configuration is 1s^(2), 2s^(2)2p^(6), 3s^(2) is a // an
The element whose electronic configuration is 1s^(2), 2s^(2)2p^(6), 3s^(2) is a // an
The electronic configuration for the following atoms are given below : a. 1s^(2) 2s^(2) 2p^(5) , b. 1s^(2) 2s^(2) 2p^(4) , c. 1s^(2) 2s^(2) 2p^(6) 3s^(2) d. 1s^(2)2s^(2) 2p^(6) , e. 1s^(2)2s^(2)2p^(6) 3s^(1) i. From the above configuration, arrange them in decreasing IE . ii. Which of the electronic configuration given above wil have the lowest IE ? iii. Which of the electronic configuration given above will be for noble gases ?
name the element with electronic configuration 1s^(2) 2s^(2) 2p^(6)3s^(2)
The electronic configuration of metal M is 1s^(2)2s^(2)2p^(6)3s^(1). The formula of its oxide will be :
The atomic number of chromium is 24 Its electronic coefigueration in ground state in 1s^(2) 2s^(2)2p^(6)3s^(2)4s^(1) 3d^(5) .Chromium atom by using 3 electron from Cr ^(3+) .A chromium atom contain 17% morte neutron than the proton. Now answer the following questions The number of unpaired electron in Cr ^(3+) ion is
