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Read the following statements and choose...

Read the following statements and choose the correct option. (I) If the radius of the first Bohr orbit of hydrogen atom is r and of `2^(nd)` orbit of `Li^(2+)` would be 4r. (II) For s-orbital electron , the orbital angular momentum is zero

A

only I is correct

B

only II is correct

C

bothare correct

D

both are incorrect

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the two statements provided and determine their correctness. ### Step 1: Analyze the first statement The first statement claims that if the radius of the first Bohr orbit of the hydrogen atom is \( r \), then the radius of the second orbit of \( \text{Li}^{2+} \) would be \( 4r \). 1. **Bohr's Radius Formula**: The radius of the \( n \)-th Bohr orbit for hydrogen-like atoms is given by the formula: \[ r_n = a_0 \frac{n^2}{Z} \] where \( a_0 \) is the Bohr radius (approximately \( 0.529 \) Å), \( n \) is the principal quantum number, and \( Z \) is the atomic number. 2. **Calculate for Hydrogen**: For hydrogen (\( Z = 1 \)) and the first orbit (\( n = 1 \)): \[ r_1 = a_0 \frac{1^2}{1} = a_0 = 0.529 \text{ Å} = r \] 3. **Calculate for \( \text{Li}^{2+} \)**: For lithium (\( Z = 3 \)) and the second orbit (\( n = 2 \)): \[ r_2 = a_0 \frac{2^2}{3} = a_0 \frac{4}{3} = 0.529 \times \frac{4}{3} \approx 0.529 \times 1.33 \approx 0.706 \text{ Å} \] Since \( r \) (the radius of the first orbit of hydrogen) is \( 0.529 \) Å, we find: \[ r_2 \approx 1.33r \] Therefore, the statement that \( r_2 = 4r \) is incorrect. ### Step 2: Analyze the second statement The second statement claims that for an s-orbital electron, the orbital angular momentum is zero. 1. **Orbital Angular Momentum Formula**: The orbital angular momentum \( L \) is given by: \[ L = \sqrt{l(l + 1)} \frac{h}{2\pi} \] where \( l \) is the azimuthal quantum number. 2. **For s-orbital**: For s-orbitals, \( l = 0 \): \[ L = \sqrt{0(0 + 1)} \frac{h}{2\pi} = \sqrt{0} = 0 \] Thus, the orbital angular momentum for an s-electron is indeed zero. ### Conclusion - The first statement is incorrect. - The second statement is correct. The correct option is **B** (only the second statement is correct).
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