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Which of the following has the maximum n...

Which of the following has the maximum number of unpaired electrons?

A

Mn

B

Ti

C

V

D

Al

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given elements has the maximum number of unpaired electrons, we will analyze the electronic configurations of each element step by step. ### Step 1: Identify the Elements and Their Atomic Numbers The elements provided are: 1. Manganese (Mn) - Atomic Number 25 2. Titanium (Ti) - Atomic Number 22 3. Vanadium (V) - Atomic Number 23 4. Aluminum (Al) - Atomic Number 13 ### Step 2: Write the Electronic Configurations Next, we write the electronic configurations for each element. 1. **Manganese (Mn)**: - Atomic Number: 25 - Electronic Configuration: \( \text{[Ar]} \, 3d^5 \, 4s^2 \) 2. **Titanium (Ti)**: - Atomic Number: 22 - Electronic Configuration: \( \text{[Ar]} \, 3d^2 \, 4s^2 \) 3. **Vanadium (V)**: - Atomic Number: 23 - Electronic Configuration: \( \text{[Ar]} \, 3d^3 \, 4s^2 \) 4. **Aluminum (Al)**: - Atomic Number: 13 - Electronic Configuration: \( \text{[Ne]} \, 3s^2 \, 3p^1 \) ### Step 3: Determine the Number of Unpaired Electrons Now, we will determine the number of unpaired electrons for each element based on their electronic configurations. 1. **Manganese (Mn)**: - Configuration: \( 3d^5 \, 4s^2 \) - In the 3d subshell, there are 5 electrons. According to Hund's rule, each of the 5 d orbitals will have one unpaired electron before any pairing occurs. The 4s subshell has 2 paired electrons. - **Total Unpaired Electrons = 5 (from 3d)** 2. **Titanium (Ti)**: - Configuration: \( 3d^2 \, 4s^2 \) - In the 3d subshell, there are 2 electrons. Both will occupy separate orbitals, leading to 2 unpaired electrons. The 4s subshell has 2 paired electrons. - **Total Unpaired Electrons = 2 (from 3d)** 3. **Vanadium (V)**: - Configuration: \( 3d^3 \, 4s^2 \) - In the 3d subshell, there are 3 electrons. Each will occupy separate orbitals, leading to 3 unpaired electrons. The 4s subshell has 2 paired electrons. - **Total Unpaired Electrons = 3 (from 3d)** 4. **Aluminum (Al)**: - Configuration: \( 3s^2 \, 3p^1 \) - In the 3p subshell, there is 1 electron, which is unpaired. The 3s subshell has 2 paired electrons. - **Total Unpaired Electrons = 1 (from 3p)** ### Step 4: Compare the Number of Unpaired Electrons Now, we summarize the number of unpaired electrons for each element: - Manganese (Mn): 5 unpaired electrons - Titanium (Ti): 2 unpaired electrons - Vanadium (V): 3 unpaired electrons - Aluminum (Al): 1 unpaired electron ### Conclusion The element with the maximum number of unpaired electrons is **Manganese (Mn)** with **5 unpaired electrons**.
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