Which of the following orbitals has two spherical nodes?
A
(a) 2s
B
(b) 4s
C
(c) 3d
D
(d) 6f
Text Solution
AI Generated Solution
The correct Answer is:
To determine which orbital has two spherical nodes, we need to analyze the concept of nodes in atomic orbitals. Here’s a step-by-step solution:
### Step 1: Understand the Concept of Nodes
Nodes are regions in an atomic orbital where the probability of finding an electron is zero. There are two types of nodes:
- **Spherical (Radial) Nodes**: These are spherical surfaces where the probability of finding an electron is zero.
- **Angular Nodes**: These are planar surfaces where the probability of finding an electron is zero.
### Step 2: Identify the Formula for Nodes
The total number of nodes in an orbital is given by the formula:
\[ \text{Total Nodes} = n - 1 \]
where \( n \) is the principal quantum number.
The number of spherical (radial) nodes can be calculated using:
\[ \text{Radial Nodes} = n - l - 1 \]
where \( l \) is the azimuthal quantum number.
### Step 3: Calculate Nodes for Different Orbitals
Now, let’s calculate the number of spherical nodes for various orbitals:
1. **1s Orbital**:
- \( n = 1 \), \( l = 0 \)
- Total Nodes = \( 1 - 1 = 0 \)
- Radial Nodes = \( 1 - 0 - 1 = 0 \)
2. **2s Orbital**:
- \( n = 2 \), \( l = 0 \)
- Total Nodes = \( 2 - 1 = 1 \)
- Radial Nodes = \( 2 - 0 - 1 = 1 \)
3. **3s Orbital**:
- \( n = 3 \), \( l = 0 \)
- Total Nodes = \( 3 - 1 = 2 \)
- Radial Nodes = \( 3 - 0 - 1 = 2 \)
4. **4s Orbital**:
- \( n = 4 \), \( l = 0 \)
- Total Nodes = \( 4 - 1 = 3 \)
- Radial Nodes = \( 4 - 0 - 1 = 3 \)
5. **3d Orbital**:
- \( n = 3 \), \( l = 2 \)
- Total Nodes = \( 3 - 1 = 2 \)
- Radial Nodes = \( 3 - 2 - 1 = 0 \)
6. **6f Orbital**:
- \( n = 6 \), \( l = 3 \)
- Total Nodes = \( 6 - 1 = 5 \)
- Radial Nodes = \( 6 - 3 - 1 = 2 \)
### Step 4: Conclusion
From the calculations above, we find that the **6f orbital** has **two spherical nodes**.
### Final Answer
The orbital that has two spherical nodes is **6f**.
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