What will be the effect of the equilibrium constant on increasing temperature. If the reaction neither absorbs heat nor releases heat?

Options

A. Equililbrium constant will remain constant.
B. Equilibrium constant will decrease .
C. Equilibrium constant will increase.
D. Can not be predicted.

Answer

To determine the effect of temperature on the equilibrium constant for a reaction that neither absorbs nor releases heat, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Meaning of ΔH = 0**:
- Since the reaction neither absorbs nor releases heat, the change in enthalpy (ΔH) is zero. This indicates that the reaction is neither exothermic nor endothermic.

2. **Use the Relationship Between Equilibrium Constants and Temperature**:
- The relationship between the equilibrium constants at two different temperatures (K1 at T1 and K2 at T2) is given by the equation:
\[ \ln \left(\frac{K_2}{K_1}\right) = \frac{\Delta H}{2.303 R} \left(\frac{1}{T_1} - \frac{1}{T_2}\right) \]
- Here, R is the universal gas constant.

3. **Substitute ΔH = 0 into the Equation**:
- Since ΔH = 0, the equation simplifies to:
\[ \ln \left(\frac{K_2}{K_1}\right) = 0 \]

4. **Interpret the Result**:
- The natural logarithm of a number is zero only when that number is 1. Therefore:
\[ \frac{K_2}{K_1} = 1 \]
- This implies that:
\[ K_2 = K_1 \]
- Thus, the equilibrium constant does not change with temperature.

5. **Conclusion**:
- The equilibrium constant remains constant when the temperature is increased for a reaction that neither absorbs nor releases heat. Therefore, the answer is that the equilibrium constant will remain constant.