Home
Class 11
CHEMISTRY
For the reaction H(2)(g)+I(2)(g)hArr2HI(...

For the reaction `H_(2)(g)+I_(2)(g)hArr2HI(g)`
the equilibrium constant `K_(p)` changes with

A

total pressure

B

catalyst

C

concentration of`H_(2)and I_(2)`

D

temperature

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equilibrium constant \( K_p \) for the reaction \[ H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \] we need to understand how the equilibrium constant behaves under different conditions. Here’s a step-by-step solution: ### Step 1: Understanding the Equilibrium Constant The equilibrium constant \( K_p \) is defined for a given reaction at equilibrium. It is a ratio of the partial pressures of the products to the partial pressures of the reactants, each raised to the power of their stoichiometric coefficients. ### Step 2: Factors Affecting \( K_p \) The equilibrium constant \( K_p \) is influenced by several factors, but it is crucial to note that it does not change with changes in concentration, pressure, or the presence of a catalyst. The only factor that can change \( K_p \) is temperature. ### Step 3: Temperature Dependence For a reaction at equilibrium, if the temperature changes, the value of \( K_p \) will also change. This is because the equilibrium position shifts to either favor the formation of products or reactants depending on whether the reaction is endothermic or exothermic. - **Endothermic Reaction**: If the reaction absorbs heat, increasing the temperature will shift the equilibrium to the right, increasing \( K_p \). - **Exothermic Reaction**: If the reaction releases heat, increasing the temperature will shift the equilibrium to the left, decreasing \( K_p \). ### Step 4: Conclusion Thus, for the reaction \( H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \), the equilibrium constant \( K_p \) changes only with temperature. ### Final Answer The equilibrium constant \( K_p \) changes with temperature. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction N_(2)(g)+O_(2)(g) hArr 2NO(g) , the equilibrium constant is K_(1) . The equilibrium constant is K_(2) for the reaction 2NO(g)+O_(2) hArr 2NO_(2)(g) What is K for the reaction NO_(2)(g) hArr 1/2 N_(2)(g)+O_(2)(g) ?

For the reaction H_(2)(g) + I_(2)(g)hArr2HI(g) at 721 K the value of equilibrium constant (K_(c)) is 50. When the equilibrium concentration of both is 0.5 M, the value of K_(p) under the same condtions will be

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) , the equilibrium can be shifted in favour of product by

The equilibrium constant at 717 K for the reaction: H_(2(g))+I_(2(g))lArr2HI_((g)) is 50. The equilibrium constant for the reaction: 2HI_(2(g))lArrH_(2(g))+I_(2(g)) is

For the reaction N_2(g) +O_2( g) hArr 2NO(g), the equilibrium constant is K1 and for reaction 2NO(g) +O_2(g) hArr 2NO_2(g) . equilibrium constant is K2 What is K for the reaction NO_2(g) hArr (1)/(2) N_2(g) + O_2(g)

For the reaction 2NO_(2)(g)+(1)/(2)O_(2)(g)hArrN_(2)O_(5)(g) if the equilibrium constant is K_(p) , then the equilibrium constant for the reaction 2N_(2)O_(5)(g)hArr4NO_(2)(g)+O_(2)(g) would be :

The equilibrium constant for the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) is 20 at 500K . The equilibrium constant for the reaction 2AB(g) hArr A_(2)(g)+B_(2)(g) would be

For the reaction, N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) , the units of K_(p) are …………

For the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) , the rate of reaction is expressed as

For the reaction, 2HI(g) rarr H_(2)(g) + I_(2) (g) - Q KJ , the equilibrium constant depends upon