NH(3) is heated at 15 atm, from 25^(@)C ...

`NH_(3)` is heated at `15` atm, from `25^(@)C` to `347^(@)C` assuming volume constant. The new pressure becomes `50` atm at equilibrium of the reaction `2NH_(3) hArr N_(2)+3H_(2)`. Calculate `%` moles of `NH_(3)` actually decomposed.

A

(a) `65%`

B

(b) `61.3%`

C

(c) `62.5%`

D

(d) `64%`

Verified by Experts

The correct Answer is:

b

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