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For the reaction N(2)(g)+O(2)(g)hArr2N...

For the reaction
`N_(2)(g)+O_(2)(g)hArr2NO(g)`
If pressure id increased by reducing the volume of the container then :

A

total pressure at equilibrium will remain same

B

concentration of all the component at equilibrium will change

C

concentration of all the component at equilibrium will ramin same

D

equilibrium will shift in the beckward direction

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the reaction and apply Le Chatelier's principle to understand the effects of increasing pressure by reducing the volume of the container. ### Step-by-Step Solution: 1. **Identify the Reaction**: The given reaction is: \[ N_2(g) + O_2(g) \rightleftharpoons 2NO(g) \] 2. **Count the Moles of Gases**: - On the reactant side, we have: - 1 mole of \(N_2\) - 1 mole of \(O_2\) - Total = 2 moles of gas (reactants) - On the product side, we have: - 2 moles of \(NO\) - Total = 2 moles of gas (products) 3. **Apply Le Chatelier's Principle**: Le Chatelier's principle states that if a system at equilibrium is subjected to a change in pressure, temperature, or concentration, the system will adjust to counteract that change and establish a new equilibrium. - In this case, increasing the pressure by reducing the volume will favor the side with fewer moles of gas. - Since both sides of the reaction have the same number of moles (2 moles), the equilibrium position will not shift in either direction. 4. **Effect of Volume Reduction**: - Reducing the volume increases the concentration of all gaseous components because concentration is defined as the number of moles divided by the volume. - Therefore, while the equilibrium position does not shift, the concentrations of all components (reactants and products) will increase. 5. **Conclusion**: - The total pressure at equilibrium will remain the same because the number of moles of gas on both sides is equal. - However, the concentration of all components at equilibrium will change (increase). ### Final Answer: The correct statement is: **The concentration of all components at equilibrium will change (increase).** ---
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