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which of the following arrangement will...

which of the following arrangement will procedure oxygen at anode during electrolysis?

A

Dilute `H_2SO_4` with Pt electrodes

B

Fused NaOH with inert electrodes

C

Dilute `H_2SO_4` with Cu electrodes

D

Concentrated aq. NaCl with Pt electrodes

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AI Generated Solution

The correct Answer is:
To determine which arrangements will produce oxygen at the anode during electrolysis, we need to analyze each option based on the reactions that occur at the anode. Here’s a step-by-step solution: ### Step 1: Understand the Electrolysis Process In electrolysis, oxidation occurs at the anode. The species that can be oxidized will determine what is produced at the anode. ### Step 2: Analyze Each Arrangement **Arrangement A: Dilute H2SO4 with Platinum Electrodes** - Platinum electrodes are inert and do not participate in the reaction. - In dilute H2SO4, we have H⁺ ions and SO₄²⁻ ions. Additionally, water provides OH⁻ ions. - At the anode, OH⁻ ions can be oxidized to produce oxygen: \[ 4OH^- \rightarrow 2H_2O + O_2 + 4e^- \] - Therefore, oxygen is produced at the anode in this arrangement. **Arrangement B: Fused NaOH with Inert Electrodes** - Again, the inert electrodes do not participate in the reaction. - In fused NaOH, OH⁻ ions are present. - At the anode, OH⁻ ions will be oxidized to produce oxygen: \[ 4OH^- \rightarrow 2H_2O + O_2 + 4e^- \] - Thus, oxygen is produced at the anode in this arrangement as well. **Arrangement C: Dilute H2SO4 with Copper Electrodes** - Copper electrodes are not inert; they participate in the reaction. - At the anode, copper will be oxidized to Cu²⁺ ions: \[ Cu \rightarrow Cu^{2+} + 2e^- \] - Since copper is oxidized, oxygen is not produced at the anode in this arrangement. **Arrangement D: Concentrated Aqueous NaCl with Platinum Electrodes** - Platinum electrodes are inert. - In concentrated NaCl, we have Na⁺ and Cl⁻ ions, along with water providing H⁺ and OH⁻ ions. - At the anode, Cl⁻ ions will be oxidized to produce chlorine gas: \[ 2Cl^- \rightarrow Cl_2 + 2e^- \] - Therefore, chlorine is produced instead of oxygen in this arrangement. ### Step 3: Conclusion From the analysis: - **Oxygen is produced at the anode in Arrangement A (dilute H2SO4 with platinum electrodes) and Arrangement B (fused NaOH with inert electrodes).** - **Arrangements C and D do not produce oxygen at the anode.** ### Final Answer The correct arrangements that produce oxygen at the anode during electrolysis are **A and B**. ---
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