Home
Class 11
CHEMISTRY
STATEMENT-1: If SRP of substance is -0.5...

STATEMENT-1: If SRP of substance is -0.5V, then reduction of substance is possible only in basic medium .
SRP of water is -0.8274V and at reduction potential is zero at pH=7

A

If both the statements are TRUE and STATEMENTS-2 is the correct explantion of STATEMENTS-4

B

If both the statements are TRUE but STATEMENTS-2 is NOT the correct explanation of STATEMENTS-6

C

If STATEMENTS-1 is TRUE and STATEMENTS-2 is FALSE

D

If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we need to analyze the statements provided regarding the Standard Reduction Potential (SRP) of a substance and water. ### Step-by-Step Solution: 1. **Understanding Standard Reduction Potential (SRP)**: - The Standard Reduction Potential (SRP) indicates the tendency of a substance to gain electrons (be reduced). A more positive SRP means a greater tendency to be reduced. 2. **Analyzing Statement 1**: - Statement 1 claims that if the SRP of a substance is -0.5 V, then the reduction of the substance is possible only in a basic medium. - The SRP of water is -0.8274 V, which means that at pH 7 (neutral), the reduction potential for water is zero. - For a substance with an SRP of -0.5 V, it is indeed greater than -0.8274 V. Therefore, it can be reduced in a basic medium where the potential is higher (less negative). 3. **Condition for Reduction**: - The condition for reduction in basic medium is that the SRP of the substance must be greater than the SRP of water (which is -0.8274 V). - In this case, since -0.5 V is greater than -0.8274 V, reduction is possible in basic medium. 4. **Conclusion for Statement 1**: - Thus, Statement 1 is **True**. 5. **Analyzing Statement 2**: - Statement 2 claims that the SRP of water is -0.8274 V. - However, the correct SRP of water is actually -1.23 V. - Therefore, this statement is **False**. 6. **Final Answer**: - Since Statement 1 is True and Statement 2 is False, the correct answer is that Statement 1 is true and Statement 2 is false. ### Summary: - **Statement 1**: True - **Statement 2**: False - **Final Answer**: C (Statement 1 is true, Statement 2 is false)
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI ENGLISH|Exercise Subjective problems|14 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI ENGLISH|Exercise Match the column|6 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI ENGLISH|Exercise leval-03|23 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI ENGLISH|Exercise Subjective problems|15 Videos

Similar Questions

Explore conceptually related problems

STATEMENT-1: If SRP of substance is -0.3V, its reduction is possible at cathode. STATEMENT-2: Reduction potential of water lies between 0 to -0.8274 V at 25^(@)

0.1M solution of which of the substances will behave basic?

At What pH oxidation potential of water is -0.81V ?

STATEMENT-1: If SOP of substance is less than -1.23 V and over voltage=0V, then its oxidation in its aqueous solution is not possible at 298 K. , STATEMENT-2: Standard reduction potential (SRP) of water is +1.23V.

STATEMENT-1: The standard reduction potentlal of M^(n^(+))//M electrode increases with increase in activity of M^(n+) ion. and STATEMENT-2: The standard reduction potential is given by: E_(RP)=E_(RP)^@+(0.059)/(n) log [M^(n+)]

The standard oxidation potential for the half-cell NO_(2)^(-)(g)+H_(2)OtoNO_(3)^(-)(aq)+2H^(+)(aq)+2e is -0.78V . Calculate the reduction in 9 molar H^(+) assuming all other species at unit concentration. What will be the reduction potential in neutral medium?

How many moles of electrons are needed for the reduction of 20mL of 0.5M solution of KMnO_(4) in acid medium

The electrode potential, E^(@) , for the reduction of MnO_(4)^(-)" to "Mn^(2+) in acidic medium is +1.51V . Which of the following metal(s) will be oxidised? The reduction reactions and standard electrode potentials for Zn^(2+), Ag^(+) and Au^(+) are given as Zn_((aq))^(2+)+2e^(-)rarrZn_((s)),E^(@)=-0.762V Ag_((aq))^(+)+e^(-)hArr Ag_((x)), E^(@)=+0.80V Au_((aq))^(+)+e^(-)hArr Au_((s)), E^(@)=+1.69V

A hollow metallic sphere of radius 0.1 m is charged to a potential of 5 V. The potential at its centre is

How much will the reduction potential of a hydrogen electrode change when its solution initially at pH=0 is neutralized to pH=7 ?