STATEMENT-1: If SOP of substance is less than -1.23 V and over voltage=0V, then its oxidation in its aqueous solution is not possible at 298 K. ,
STATEMENT-2: Standard reduction potential (SRP) of water is +1.23V.

Options

A. If both the statements are TRUE and STATEMENTS-2 is the correct explantion of STATEMENTS-8
B. If both the statements are TRUE but STATEMENTS-2 is NOT the correct explanation of STATEMENTS-10
C. If STATEMENTS-1 is TRUE and STATEMENTS-2 is FALSE
D. If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE

Answer

To solve the question, we need to analyze both statements given in the problem.

### Step 1: Analyze Statement 1
Statement 1 claims that if the standard oxidation potential (SOP) of a substance is less than -1.23 V and the overvoltage is 0 V, then its oxidation in an aqueous solution is not possible at 298 K.

- The standard reduction potential (SRP) of water is +1.23 V, which means the oxidation potential of water is -1.23 V (since oxidation is the reverse of reduction).
- For a substance to be oxidized in an aqueous solution, its SOP must be greater than -1.23 V (i.e., it should be less negative than -1.23 V).
- Therefore, if the SOP of the substance is less than -1.23 V, it cannot be oxidized because it is more negative than the oxidation potential of water.

**Conclusion for Statement 1:** True.

### Step 2: Analyze Statement 2
Statement 2 states that the standard reduction potential (SRP) of water is +1.23 V.

- This is incorrect because the standard reduction potential of water is actually -1.23 V when considering the oxidation reaction (2H₂O → O₂ + 4H⁺ + 4e⁻).
- The correct statement should be that the SRP of water is -1.23 V for the reduction of water to oxygen.

**Conclusion for Statement 2:** False.

### Final Conclusion
- Statement 1 is true.
- Statement 2 is false.

Thus, the answer is that Statement 1 is true and Statement 2 is false.