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Total vapour pressure of mixture of 1 m...

Total vapour pressure of mixture of 1 mole of volaile components A (`P_(a^(%)`)=100 mm Hg) and 3 mole of volatile component B(`P_B^(@) =80 mm Hg`) is 90 mm Hg. For such case:

A

There is positive deviation from Rsoult's law

B

boiling point has been lowered

C

force of attraction between A and B is weaker than that between A and A or betweenB and B

D

All the above statement are correct

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To solve the problem step by step, we need to find the total vapor pressure of a mixture of two volatile components A and B and analyze the deviation from Raoult's law. ### Step 1: Identify the given data - Moles of component A (n_A) = 1 mole - Vapor pressure of pure component A (P_A^0) = 100 mm Hg - Moles of component B (n_B) = 3 moles - Vapor pressure of pure component B (P_B^0) = 80 mm Hg - Total vapor pressure of the mixture (P_total) = 90 mm Hg ### Step 2: Calculate the total number of moles in the mixture Total moles (n_total) = n_A + n_B = 1 + 3 = 4 moles ### Step 3: Calculate the mole fractions of components A and B - Mole fraction of A (X_A) = n_A / n_total = 1 / 4 = 0.25 - Mole fraction of B (X_B) = n_B / n_total = 3 / 4 = 0.75 ### Step 4: Calculate the ideal vapor pressure of the mixture (P_ideal) Using Raoult's law, the ideal vapor pressure (P_ideal) can be calculated as: \[ P_{ideal} = P_A^0 \cdot X_A + P_B^0 \cdot X_B \] Substituting the values: \[ P_{ideal} = (100 \, \text{mm Hg} \cdot 0.25) + (80 \, \text{mm Hg} \cdot 0.75) \] Calculating: \[ P_{ideal} = 25 \, \text{mm Hg} + 60 \, \text{mm Hg} = 85 \, \text{mm Hg} \] ### Step 5: Compare P_ideal with P_total We have: - P_ideal = 85 mm Hg - P_total = 90 mm Hg Since P_total > P_ideal, this indicates a positive deviation from Raoult's law. ### Step 6: Analyze the implications of positive deviation 1. **Boiling Point**: The boiling point of the solution is lowered because the total vapor pressure is higher than expected for an ideal solution. 2. **Forces of Attraction**: The forces of attraction between A and B are weaker than those between A and A or B and B, leading to the positive deviation. ### Conclusion Based on the analysis: - The solution exhibits positive deviation from Raoult's law. - The boiling point is lowered. - The forces of attraction between A and B are weaker than those between A and A or B and B. Thus, the correct answer is option D.
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