Azeotropic mixture of water and `C_(2)H_(5)OH` boils at 351 K. By distilling the mixture it is possible to obtain

Options

A. pure `C_(2)H_(5)OH ` only
B. Pure water only
C. Neither`C_(2)H_(5)OH` nor water
D. Both water and `C_(2)H_(5)OH` in pure state

Answer

To solve the problem regarding the azeotropic mixture of water and ethanol (C₂H₅OH) that boils at 351 K, we need to understand the nature of azeotropes and what can be obtained from distillation.

### Step-by-Step Solution:

1. **Understanding Azeotropes**:
- An azeotropic mixture is a mixture of two or more liquids that has a constant boiling point and composition throughout the distillation process. This means that when the mixture is boiled, the vapor produced has the same composition as the liquid mixture.

2. **Composition of the Mixture**:
- In the case of the azeotropic mixture of water and ethanol, the boiling point is given as 351 K. At this temperature, the mixture will not separate into pure components upon boiling.

3. **Distillation Process**:
- During distillation of an azeotropic mixture, the vapor that forms will have the same ratio of components as the liquid mixture. Therefore, no matter how much you distill, you will not be able to obtain pure ethanol or pure water.

4. **Conclusion**:
- Since the question asks what can be obtained from distilling the azeotropic mixture, the answer is that it is not possible to obtain pure ethanol or pure water. The composition remains constant, and you will continue to get a mixture of water and ethanol.

### Final Answer:
By distilling the azeotropic mixture of water and ethanol that boils at 351 K, it is not possible to obtain pure ethanol or pure water. The distillation will yield a mixture with the same composition as the original azeotropic mixture.