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Assuming each salt to be 90% dissociated...

Assuming each salt to be `90%` dissociated which of the following will have the highest osmotic pressure?

A

decimolar aluminium sulphate

B

decimolar barium chloride solution

C

decimolar sodium sulphate solution

D

solution of volume of decimolar barium choride and decimolar sodium suphate solutions

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The correct Answer is:
To determine which salt solution has the highest osmotic pressure when each salt is assumed to be 90% dissociated, we can follow these steps: ### Step 1: Understand the Osmotic Pressure Formula The osmotic pressure (π) is given by the formula: \[ \pi = C \cdot R \cdot T \cdot i \] Where: - \( C \) = concentration of the solution - \( R \) = gas constant - \( T \) = temperature - \( i \) = Van't Hoff factor (the number of particles the solute dissociates into) ### Step 2: Identify the Van't Hoff Factor for Each Salt We will calculate the Van't Hoff factor \( i \) for each salt based on their dissociation: 1. **Aluminum Sulfate (Al₂(SO₄)₃)**: - Dissociates into: \( 2 \text{Al}^{3+} + 3 \text{SO}_4^{2-} \) - Total particles = \( 2 + 3 = 5 \) - \( i = 5 \) - Considering 90% dissociation: \[ i_{effective} = 0.9 \times 5 = 4.5 \] 2. **Barium Chloride (BaCl₂)**: - Dissociates into: \( \text{Ba}^{2+} + 2 \text{Cl}^- \) - Total particles = \( 1 + 2 = 3 \) - \( i = 3 \) - Considering 90% dissociation: \[ i_{effective} = 0.9 \times 3 = 2.7 \] 3. **Sodium Sulfate (Na₂SO₄)**: - Dissociates into: \( 2 \text{Na}^+ + \text{SO}_4^{2-} \) - Total particles = \( 2 + 1 = 3 \) - \( i = 3 \) - Considering 90% dissociation: \[ i_{effective} = 0.9 \times 3 = 2.7 \] ### Step 3: Compare the Effective Van't Hoff Factors Now we compare the effective Van't Hoff factors we calculated: - Aluminum Sulfate: \( i_{effective} = 4.5 \) - Barium Chloride: \( i_{effective} = 2.7 \) - Sodium Sulfate: \( i_{effective} = 2.7 \) ### Step 4: Determine the Highest Osmotic Pressure Since the concentration \( C \), gas constant \( R \), and temperature \( T \) are the same for all solutions, the osmotic pressure is directly proportional to the effective Van't Hoff factor \( i \). Therefore, the solution with the highest \( i \) will have the highest osmotic pressure. ### Conclusion The solution with the highest osmotic pressure is the **decimolar aluminum sulfate solution**.
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