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A solution contain 8 g of a carbohydrate...

A solution contain 8 g of a carbohydrate in 100 g of water has a density 1.025 g/mL and an osmotic pressure of 5 atm at `27^(@) C`. What is the molar mass of the carbohydrate?

A

387

B

374

C

3740

D

None of these

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The correct Answer is:
To find the molar mass of the carbohydrate in the solution, we will follow these steps: ### Step 1: Identify the given data - Mass of the carbohydrate (solute), W = 8 g - Mass of water (solvent) = 100 g - Density of the solution = 1.025 g/mL - Osmotic pressure (π) = 5 atm - Temperature (T) = 27°C = 300 K (after converting to Kelvin) ### Step 2: Calculate the total mass of the solution The total mass of the solution (m_solution) is the sum of the mass of the solute and the mass of the solvent: \[ m_{\text{solution}} = W + \text{mass of water} = 8 \, \text{g} + 100 \, \text{g} = 108 \, \text{g} \] ### Step 3: Calculate the volume of the solution Using the density formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] We can rearrange this to find the volume (V): \[ V = \frac{m_{\text{solution}}}{\text{Density}} = \frac{108 \, \text{g}}{1.025 \, \text{g/mL}} \] Calculating this gives: \[ V \approx 105.37 \, \text{mL} = 0.10537 \, \text{L} \] ### Step 4: Use the osmotic pressure formula The osmotic pressure formula is given by: \[ \pi = i \cdot C \cdot R \cdot T \] For a non-electrolyte like a carbohydrate, \( i = 1 \), so: \[ \pi = C \cdot R \cdot T \] Where \( C \) is the concentration in moles per liter (mol/L). Rearranging gives: \[ C = \frac{\pi}{R \cdot T} \] ### Step 5: Calculate the concentration (C) Substituting the known values: - \( \pi = 5 \, \text{atm} \) - \( R = 0.0821 \, \text{L atm/(K mol)} \) - \( T = 300 \, \text{K} \) Calculating \( C \): \[ C = \frac{5}{0.0821 \cdot 300} \] \[ C \approx 0.202 \, \text{mol/L} \] ### Step 6: Calculate the number of moles of carbohydrate Using the concentration and the volume of the solution: \[ n = C \cdot V = 0.202 \, \text{mol/L} \cdot 0.10537 \, \text{L} \] Calculating this gives: \[ n \approx 0.0213 \, \text{mol} \] ### Step 7: Calculate the molar mass (M) The molar mass is calculated using the formula: \[ M = \frac{W}{n} \] Substituting the values: \[ M = \frac{8 \, \text{g}}{0.0213 \, \text{mol}} \] Calculating this gives: \[ M \approx 375.93 \, \text{g/mol} \] ### Conclusion The molar mass of the carbohydrate is approximately **374 g/mol**. ---
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