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Which of the following is correct for a non-ideal solution of liquids A and B showing negative deviation?

A

`/_\H_("mix") = - ve`

B

`/_\V_("mix") = - ve`

C

`/_\S_("mix") = - ve`

D

`/_\G_("mix") = - ve`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the properties of a non-ideal solution of liquids A and B that show negative deviation, we can follow these steps: ### Step 1: Understand Negative Deviation In a non-ideal solution that shows negative deviation, the intermolecular forces between the components A and B are stronger than those in the pure components A and B. This leads to a reduction in vapor pressure compared to what would be expected from Raoult's law. **Hint:** Consider how intermolecular forces affect vapor pressure in solutions. ### Step 2: Analyze Vapor Pressure For a non-ideal solution with negative deviation, the observed vapor pressure (P_observed) is less than the ideal vapor pressure (P_ideal). Mathematically, this can be expressed as: - P_observed < P_ideal - P_observed < P0A * xA (for component A) - P_observed < P0B * xB (for component B) **Hint:** Recall that Raoult's law applies to ideal solutions, and deviations indicate differences in intermolecular interactions. ### Step 3: Examine Enthalpy of Mixing (ΔH_mixing) For solutions that show negative deviation, the enthalpy of mixing (ΔH_mixing) is negative. This indicates that heat is released when the solute and solvent are mixed. **Hint:** Think about the energy changes that occur when two substances mix. ### Step 4: Consider Volume Change (ΔV_mixing) The volume change upon mixing (ΔV_mixing) is also negative for solutions showing negative deviation. This means that the total volume of the solution is less than the sum of the volumes of the pure components. **Hint:** Reflect on how the arrangement of molecules changes when they mix. ### Step 5: Analyze Entropy of Mixing (ΔS_mixing) The entropy of mixing (ΔS_mixing) is negative for solutions that show negative deviation. This is because the release of heat during mixing leads to a decrease in the randomness or disorder of the system. **Hint:** Relate entropy to the disorder of a system and how mixing affects it. ### Step 6: Evaluate Gibbs Free Energy of Mixing (ΔG_mixing) The Gibbs free energy of mixing (ΔG_mixing) can be expressed as: - ΔG_mixing = ΔH_mixing - TΔS_mixing Since both ΔH_mixing and ΔS_mixing are negative, the sign of ΔG_mixing will depend on the magnitudes of these terms. Therefore, we cannot definitively say that ΔG_mixing is always negative. **Hint:** Consider how temperature affects the relationship between enthalpy and entropy in determining the spontaneity of mixing. ### Conclusion From the analysis, we can conclude that: - ΔH_mixing < 0 (heat is evolved) - ΔV_mixing < 0 (volume decreases) - ΔS_mixing < 0 (entropy decreases) - ΔG_mixing cannot be definitively stated as negative. Thus, the correct options for a non-ideal solution of liquids A and B showing negative deviation are: - ΔH_mixing is negative - ΔV_mixing is negative - ΔS_mixing is negative ### Final Answer The correct options are: ΔH_mixing < 0, ΔV_mixing < 0, ΔS_mixing < 0. The statement regarding ΔG_mixing is incorrect as it depends on the magnitudes of ΔH and TΔS.
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