Given the following `K_(a)` values, determine which species is the strongest base ? `HSO_(4)^(-)=1.2xx10^(-2),H_(2)PO_(4)^(-)=6.3xx10^(-8),HCO_(3)^(-)=4.7xx10^(-11)`
(a)`CO_(3)^(2-)`
(b)`H_(2)SO_(4)`
(c)`SO_(4)^(2-)`
(d)`HPO_(4)^(2-)`
A
`CO_(3)^(2-)`
B
`H_(2)SO_(4)`
C
`SO_(4)^(2-)`
D
`HPO_(4)^(2-)`
Text Solution
AI Generated Solution
The correct Answer is:
To determine which species is the strongest base among the given options based on the provided \( K_a \) values, we can follow these steps:
### Step 1: Understand the relationship between \( K_a \) and strength of acids
The strength of an acid is directly related to its \( K_a \) value. A larger \( K_a \) value indicates a stronger acid, which means it dissociates more in solution, producing more \( H^+ \) ions.
### Step 2: Identify the \( K_a \) values provided
The given \( K_a \) values are:
- \( HSO_4^- = 1.2 \times 10^{-2} \)
- \( H_2PO_4^- = 6.3 \times 10^{-8} \)
- \( HCO_3^- = 4.7 \times 10^{-11} \)
### Step 3: Determine the order of acid strength
From the \( K_a \) values, we can rank the acids in terms of their strength:
1. \( HSO_4^- \) (strongest acid)
2. \( H_2PO_4^- \)
3. \( HCO_3^- \) (weakest acid)
### Step 4: Identify the conjugate bases
The conjugate bases of these acids are:
- The conjugate base of \( HSO_4^- \) is \( SO_4^{2-} \)
- The conjugate base of \( H_2PO_4^- \) is \( HPO_4^{2-} \)
- The conjugate base of \( HCO_3^- \) is \( CO_3^{2-} \)
### Step 5: Determine the strength of the conjugate bases
The strength of a base is inversely related to the strength of its conjugate acid. Therefore:
- The conjugate base of the strongest acid \( HSO_4^- \) (which is \( SO_4^{2-} \)) will be the weakest base.
- The conjugate base of the medium strength acid \( H_2PO_4^- \) (which is \( HPO_4^{2-} \)) will be stronger than \( SO_4^{2-} \).
- The conjugate base of the weakest acid \( HCO_3^- \) (which is \( CO_3^{2-} \)) will be the strongest base.
### Step 6: Compare the bases
Based on the above analysis, we can rank the bases:
1. \( CO_3^{2-} \) (strongest base)
2. \( HPO_4^{2-} \)
3. \( SO_4^{2-} \) (weakest base)
### Conclusion
Thus, the strongest base among the given options is:
**(a) \( CO_3^{2-} \)**
---
Classify the following into acid base and amphiprotic species on the basis of protonic concept : H_(2)PO_(2)^(-) (ii) H_(2)PO_(3)^(-),(III) H_(2)PO_(4)^(-),(iv) HPO_(3)^(2-),(v)HPO_(4)^(2-)(vi)NH_(4)^(+) (vii)CH_(3)COOH_(2)^(+)
The pH of a solution containing 0.4 M HCO_(3)^(-) and 0.2 M CO_(3)^(2-) is : [K_(a1)(H_(2)CO_(3))=4xx10^(-7) , K_(a2)(HCO_(3)^(-))=4xx10^(-11)]
In which direction will the following equilibria I and II proceed? I:H_(2)SO_(4)(aq)+NH_(3)(aq)hArrNH_(4)^(+)(aq)+HSO_(4)^(-)(aq) II: HCO_(3)^(-)(aq)+SO_(4)^(-)(aq)hArr HSO_(4)^(-)(aq)+CO_(3)^(2-)(aq)
Total number of species that can be oxidzed by acidic permanganate ion (MnO_(4)^(-)//H^(+)) . I^(-),Fe^(2+),CO_(2),C_(2)O_(4)^(2-),S^(2-),SO_(3)^(2-),NO_(2)^(2-),PO_(4)^(3-),SO_(4)^(2-)
Which of the following consitute a set of amphoteric species? (a). H_(2)O,H_(2)PO_(3)^(Theta), HPO_(4)^(2-) (b). HC_(2)O_(4)^(Theta),H_(2)PO_(4)^(Theta),SO_(4)^(2-) (c). H_(2)O,HPO_(4)^(2-),H_(2)PO_(2)^(Theta) (d). H_(3)O^(o+),H_(2)PO_(4)^(Theta),HCO_(3)^(Theta)
What is the sum of basicity of H_(3)PO_(4),H_(3)PO_(3),H_(3)PO_(2),H_(3)BO_(3),(COOH)_(2),H_(2)S_(2)O_(8),H_(2)SO_(4),H_(2)SO_(3),H_(2)CO_(3),H_(2)S and H_(4)P_(2)O_(5) ?
Given below are the dissociation constant values of few acids. Arrange them in order of increasing acidic strength. H_(2)SO_(3)=1.3xx10^(-2),HNO_(2)=4xx10^(-4) CH_(3)COOH=1.8xx10^(-5),HCN=4xx10^(-10)
A saturated solution of Ca_(3)(PO_(4))_(2) has [Ca^(2+)]=2xx10^(-8) M and [PO_(4)^(3-)]=1.6xx10^(-5) M K_(sp) of Ca_(3)(PO_(4))_(2) is :
Calculate the concentration of all species of significant concentrations presents in 0.1 M H_(3)PO_(4) solution. lf K_(1) = 7.5 xx 10^(-3), K_(2) = 6.2 xx 10^(-8), K_(3) = 3.6 xx 10^(-13)
The total number of diprotic acids among the following is H_(3)PO_(4), H_(2)SO_(4), H_(3)PO_(3) H_(2)CO_(3), H_(2)S_(2)O_(7), H_(3)BO_(3) H_(3)PO_(2), H_(2)CrO_(4), H_(2)SO_(3)