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pH of 10^(-6) M HCl (aq.) is :...

pH of `10^(-6)` M HCl (aq.) is :

A

just less then 6

B

exactly equal to 6

C

just greater than 6

D

just less than 7

Text Solution

AI Generated Solution

The correct Answer is:
To find the pH of a `10^(-6)` M HCl solution, we can follow these steps: ### Step 1: Understand the definition of pH The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration \([H^+]\): \[ \text{pH} = -\log[H^+] \] ### Step 2: Identify the concentration of hydrogen ions In a strong acid like HCl, it completely dissociates in water. Therefore, the concentration of hydrogen ions \([H^+]\) in a `10^(-6)` M HCl solution is: \[ [H^+] = 10^{-6} \text{ M} \] ### Step 3: Calculate the pH Now, we can substitute the value of \([H^+]\) into the pH formula: \[ \text{pH} = -\log(10^{-6}) \] ### Step 4: Simplify the logarithm Using the properties of logarithms, we can simplify: \[ \text{pH} = -(-6) \cdot \log(10) = 6 \cdot 1 = 6 \] ### Step 5: Consider the contribution of water In a solution where the concentration of HCl is `10^(-6)` M, we also have a contribution of hydrogen ions from the water itself, which is `10^(-7)` M. Therefore, the total concentration of hydrogen ions becomes: \[ [H^+]_{\text{total}} = 10^{-6} + 10^{-7} = 1.1 \times 10^{-6} \text{ M} \] ### Step 6: Recalculate the pH with the total concentration Now, we recalculate the pH using the total concentration: \[ \text{pH} = -\log(1.1 \times 10^{-6}) \] This can be approximated as: \[ \text{pH} \approx 6 - \log(1.1) \approx 6 - 0.041 = 5.96 \] ### Final Answer Thus, the pH of `10^(-6)` M HCl is approximately: \[ \text{pH} \approx 5.96 \]
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