To find the pH of a `10^(-6)` M HCl solution, we can follow these steps:
### Step 1: Understand the definition of pH
The pH of a solution is defined as the negative logarithm (base 10) of the hydrogen ion concentration \([H^+]\):
\[
\text{pH} = -\log[H^+]
\]
### Step 2: Identify the concentration of hydrogen ions
In a strong acid like HCl, it completely dissociates in water. Therefore, the concentration of hydrogen ions \([H^+]\) in a `10^(-6)` M HCl solution is:
\[
[H^+] = 10^{-6} \text{ M}
\]
### Step 3: Calculate the pH
Now, we can substitute the value of \([H^+]\) into the pH formula:
\[
\text{pH} = -\log(10^{-6})
\]
### Step 4: Simplify the logarithm
Using the properties of logarithms, we can simplify:
\[
\text{pH} = -(-6) \cdot \log(10) = 6 \cdot 1 = 6
\]
### Step 5: Consider the contribution of water
In a solution where the concentration of HCl is `10^(-6)` M, we also have a contribution of hydrogen ions from the water itself, which is `10^(-7)` M. Therefore, the total concentration of hydrogen ions becomes:
\[
[H^+]_{\text{total}} = 10^{-6} + 10^{-7} = 1.1 \times 10^{-6} \text{ M}
\]
### Step 6: Recalculate the pH with the total concentration
Now, we recalculate the pH using the total concentration:
\[
\text{pH} = -\log(1.1 \times 10^{-6})
\]
This can be approximated as:
\[
\text{pH} \approx 6 - \log(1.1) \approx 6 - 0.041 = 5.96
\]
### Final Answer
Thus, the pH of `10^(-6)` M HCl is approximately:
\[
\text{pH} \approx 5.96
\]
10 mL of 10^(-6) M HCl solution is mixed with 90mL H_(2)O . pH will change approximately:
Choose the correct code {:(,"Column"-I , "Column"-II,), ((P), pK_(b) "of" X^(-) (K_(a) "of" HX = 10^(-6)), (1), 6.9), ((Q), pH of 10^(-8) M HCl, (2),8), ((R), pH of 10^(-2) "M acetic and acid solution" (Take K_(a) of acetic acid=1.6xx10^(-5)), (3), 10.7), ((S), "pOH of a solution obtained by mixing equal volumes of solution with pH 3 and 5"., (4),3.4):}
STATEMENT-1: pH of 10^(-7) M HCl is less than 7 at 25^(@)C. STATEMENT-2: At very low concentration of HCl, contribution of H^(+) from water is considerable.
Statement-1 : pH of 10^(-7) M HCl is less than 7 at 25^@C . Statement-2 : At very low concentration of HCl, contribution of H^+ from water is considerable.
The pH of 10^(-11) M HCI at 25^@C is
A : pH of 10^(-8) M HCI solution is approx 6.9 R : HCI is a strong acid.
Calculate the pH of 10^(-8) M HCl solution .
The pH of 10^(-8) M NaOH will be
What is the pH of , (a) 5 xx 10^(-8) M HCl and (b) 5 xx 10^(-10) M HCl .