The pH values 0.1 M solution of HCOONa (I), HCOOH (II),`CH_(3)COONH_(4)` (III), NaOH (IV) HCl (V), will be in the order :
A
`IVgtIIIgtIgtIIgtV`
B
`IVgtIgtIIIgtIIgtV`
C
`IIgtIIIgtIgtIVgtV`
D
`VgtIIgtIIIgtIgtIV`
Text Solution
AI Generated Solution
The correct Answer is:
To determine the order of pH values for the given solutions of HCOONa, HCOOH, CH3COONH4, NaOH, and HCl, we need to analyze each solution based on their acidic or basic nature.
### Step-by-Step Solution:
1. **Identify the nature of each solution:**
- **HCOONa (Sodium formate)**: This is a salt derived from a weak acid (HCOOH) and a strong base (NaOH). The solution will be basic due to the hydrolysis of the formate ion (HCOO⁻).
- **HCOOH (Formic acid)**: This is a weak acid. Therefore, the solution will be weakly acidic, resulting in a pH less than 7.
- **CH3COONH4 (Ammonium acetate)**: This is a salt formed from a weak acid (acetic acid, CH3COOH) and a weak base (ammonium hydroxide, NH4OH). The solution will be neutral, as the weak acid and weak base will partially neutralize each other.
- **NaOH (Sodium hydroxide)**: This is a strong base. The solution will have a high pH (greater than 7).
- **HCl (Hydrochloric acid)**: This is a strong acid. The solution will have a low pH (less than 7).
2. **Determine the pH order based on acidity and basicity:**
- Strong Acid (HCl) will have the lowest pH.
- Weak Acid (HCOOH) will have a higher pH than HCl but lower than neutral.
- Neutral solution (CH3COONH4) will have a pH around 7.
- Weak base (HCOONa) will have a pH greater than 7.
- Strong base (NaOH) will have the highest pH.
3. **Arrange the solutions in order of increasing pH:**
- HCl (V) < HCOOH (II) < CH3COONH4 (III) < HCOONa (I) < NaOH (IV)
### Final Order of pH Values:
The order of pH values from lowest to highest is:
**HCl (V) < HCOOH (II) < CH3COONH4 (III) < HCOONa (I) < NaOH (IV)**
