Upon hydrolysis of sodium carbonate, the reaction takes place between:
A
`Na^(+)` and water
B
`Na^(+)` and `OH^(-)`
C
`CO_(3)^(2-)`and water
D
`CO_(3)^(2-)` and `H^(+)`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question regarding the hydrolysis of sodium carbonate (Na2CO3), let's break it down step by step.
### Step-by-Step Solution:
1. **Identify the Compound**:
Sodium carbonate is represented by the formula Na2CO3.
2. **Understand Hydrolysis**:
Hydrolysis refers to the reaction of a substance with water. In this case, we need to see how sodium carbonate reacts when it comes into contact with water.
3. **Write the Reaction**:
When sodium carbonate dissolves in water, it dissociates into its ions:
\[
\text{Na}_2\text{CO}_3 \rightarrow 2 \text{Na}^+ + \text{CO}_3^{2-}
\]
4. **Reaction with Water**:
The carbonate ion (CO3^2-) can react with water (H2O). The reaction can be expressed as:
\[
\text{CO}_3^{2-} + \text{H}_2\text{O} \rightleftharpoons \text{HCO}_3^- + \text{OH}^-
\]
This shows that the carbonate ion reacts with water to form bicarbonate (HCO3^-) and hydroxide ions (OH^-).
5. **Determine the Resulting Solution**:
The presence of hydroxide ions (OH^-) indicates that the solution becomes alkaline (basic).
6. **Conclusion**:
Therefore, the reaction that takes place upon hydrolysis of sodium carbonate is between the carbonate ion (CO3^2-) and water (H2O). The correct answer to the question is:
\[
\text{CO}_3^{2-} + \text{H}_2\text{O}
\]
### Final Answer:
The reaction takes place between the carbonate ion (CO3^2-) and water.
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