If a salt of strong acid and weak base hydrolyses appreciably `(alpha=0.1),` which of the following formula is to be used to calculate degree of hydrolsis 'alpha'?
A
`alpha=sqrt(K_(w))/(K_(a).a)`
B
`alpha=sqrt(K_(w))/(K_(b).a)`
C
`alpha=sqrt(K_(w))/(K_(a).K_(b)`
D
None of these
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem regarding the degree of hydrolysis (α) of a salt formed from a strong acid and a weak base, we can follow these steps:
### Step-by-Step Solution:
1. **Identify the Salt**:
- The salt formed from a strong acid and a weak base can be represented as NH4Cl (ammonium chloride), where HCl is the strong acid and NH4OH (ammonium hydroxide) is the weak base.
2. **Understand Hydrolysis**:
- When NH4Cl is dissolved in water, it dissociates into NH4⁺ (ammonium ions) and Cl⁻ (chloride ions). The ammonium ion (NH4⁺) will hydrolyze in water:
\[
NH4^+ + H2O \rightleftharpoons NH4OH + H^+
\]
- This reaction produces hydroxide ions and makes the solution acidic due to the formation of H⁺ ions.
3. **Set Up Initial Concentrations**:
- Let the initial concentration of NH4Cl be C. At equilibrium, if α is the degree of hydrolysis, the concentrations will be:
- [NH4⁺] = Cα
- [H⁺] = Cα
- [NH4OH] = C(1 - α)
4. **Write the Hydrolysis Constant Expression**:
- The hydrolysis constant (K_H) can be expressed as:
\[
K_H = \frac{[NH4OH][H^+]}{[NH4^+]} = \frac{Cα \cdot Cα}{C(1 - α)} = \frac{Cα^2}{1 - α}
\]
5. **Assume α is Small**:
- Since α = 0.1 is small compared to 1, we can approximate (1 - α) as 1:
\[
K_H \approx Cα^2
\]
6. **Relate K_H to K_a**:
- In an acidic solution, K_H is related to the dissociation constant of the acid (K_a):
\[
K_H = K_a
\]
- We can also express K_a in terms of K_w (the ion product of water) and K_b (the base dissociation constant of NH4OH):
\[
K_a = \frac{K_w}{K_b}
\]
7. **Final Formula for Degree of Hydrolysis**:
- Rearranging the equation gives:
\[
α^2 = \frac{K_a}{C}
\]
- Taking the square root to find α:
\[
α = \sqrt{\frac{K_a}{C}}
\]
- Substituting K_a with K_w/K_b gives:
\[
α = \sqrt{\frac{K_w}{K_b \cdot C}}
\]
### Final Answer:
The formula to calculate the degree of hydrolysis (α) for a salt of a strong acid and a weak base is:
\[
α = \sqrt{\frac{K_w}{K_b \cdot C}}
\]
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The degree of hydrrolysis of a salt of weak acid and weak base in its 0.1M solultion is found to be 50% . If the molarity of the solution is 0.2M , the percentage hydrolysis of the salt should be:
The degree of hydrolysis of a salt of weak acid and weak base in its 0.1M solultion is found to be 50% . If the molarity of the solution is 0.2M , the percentage hydrolysis of the salt should be:
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