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Which of the following is a buffer solut...

Which of the following is a buffer solution?

A

500 mL of 0.1 N `CH_(3)COOH+500` mL of 0.1 N NaOH

B

500 mL of 0.1 N `CH_(3)COOH+500` mL of 0.1 N HCl

C

500 mL of 0.1 N `CH_(3)COOH+500` mL of 0.2 N NaOH

D

500 mL of 0.1 N `CH_(3)COOH`+500 mL of 0.1 N `NaOH`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given options is a buffer solution, we need to understand the definition and characteristics of a buffer solution. A buffer solution is one that resists changes in pH upon the addition of small amounts of acid or base. Typically, a buffer solution consists of a weak acid and its conjugate base or a weak base and its conjugate acid. ### Step-by-Step Solution: 1. **Identify the Components of a Buffer Solution**: - A buffer solution is typically made from a weak acid and its salt (conjugate base) or a weak base and its salt (conjugate acid). - For example, acetic acid (CH₃COOH) and sodium acetate (CH₃COONa) form a buffer solution. 2. **Analyze Each Option**: - We need to evaluate the provided options to see if they meet the criteria for a buffer solution. 3. **Option 1: 500 ml of 0.1 N CH₃COOH and 500 ml of 0.1 N Ca(OH)₂**: - Here, we have a weak acid (CH₃COOH) and a strong base (Ca(OH)₂). - The reaction will neutralize the acid, but there is no conjugate base present. Therefore, this does not form a buffer solution. 4. **Option 2: 500 ml of 0.1 N CH₃COOH and 500 ml of 0.1 N HCl**: - This option consists of a weak acid (CH₃COOH) and a strong acid (HCl). - There is no weak base or conjugate base present, so this cannot form a buffer solution. 5. **Option 3: 500 ml of 0.1 N CH₃COOH and 500 ml of 0.2 N NaOH**: - In this case, we have a weak acid (CH₃COOH) and a strong base (NaOH). - The strong base will completely neutralize the weak acid, but there will be no conjugate base formed in sufficient quantity to create a buffer. Thus, this does not form a buffer solution. 6. **Option 4: 500 ml of 0.1 N CH₃COOH and 500 ml of 0.1 N NaOH**: - Here, we have a weak acid (CH₃COOH) and a strong base (NaOH). - The reaction will produce the conjugate base (sodium acetate, CH₃COONa) and water. This results in a mixture of the weak acid and its conjugate base, which qualifies as a buffer solution. ### Conclusion: The correct answer is **Option 4: 500 ml of 0.1 N CH₃COOH and 500 ml of 0.1 N NaOH**, as it forms a buffer solution.
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