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Select the best indicator from the given...

Select the best indicator from the given table for titration of 20 mL of 0.02 M `CH_(3)COOH with 0.02 M NaOH. Given `pK_(a)` `(CH_(3)COOH)=4.74`
`{:(,"Indicator","pH range"),((I),"Bromothymol blue",6.0-7.6),((II),"Thymolphthalein",9.3-10.5),((III),"Malachite green",11.4-13),((IV),"M-Cresol purple",7.4-90):}`

A

I

B

II

C

III

D

IV

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of selecting the best indicator for the titration of 20 mL of 0.02 M acetic acid (CH₃COOH) with 0.02 M sodium hydroxide (NaOH), we can follow these steps: ### Step 1: Write the Reaction The reaction between acetic acid and sodium hydroxide can be written as: \[ \text{CH}_3\text{COOH} + \text{NaOH} \rightarrow \text{CH}_3\text{COONa} + \text{H}_2\text{O} \] ### Step 2: Calculate the Initial Moles Calculate the initial moles of acetic acid and sodium hydroxide: - Moles of CH₃COOH = Volume (L) × Concentration (M) = \( 0.020 \, \text{L} \times 0.02 \, \text{mol/L} = 0.0004 \, \text{mol} \) - Moles of NaOH = Volume (L) × Concentration (M) = \( 0.020 \, \text{L} \times 0.02 \, \text{mol/L} = 0.0004 \, \text{mol} \) ### Step 3: Determine the Final Concentration of the Salt At the equivalence point, all the acetic acid will react with sodium hydroxide to form sodium acetate (CH₃COONa). The total volume after mixing will be: \[ \text{Total Volume} = 20 \, \text{mL} + 20 \, \text{mL} = 40 \, \text{mL} = 0.040 \, \text{L} \] The concentration of sodium acetate (the salt formed) will be: \[ \text{Concentration of CH}_3\text{COONa} = \frac{\text{Moles of CH}_3\text{COONa}}{\text{Total Volume}} = \frac{0.0004 \, \text{mol}}{0.040 \, \text{L}} = 0.01 \, \text{M} \] ### Step 4: Calculate the pH at the Equivalence Point At the equivalence point, we can use the formula for calculating the pH of a solution of a salt: \[ \text{pH} = \frac{1}{2} \left( pK_w + pK_a + \log C \right) \] Where: - \( pK_w = 14 \) - \( pK_a = 4.74 \) - \( C = 0.01 \, \text{M} \) Calculating: 1. \( \log(0.01) = -2 \) 2. Substitute the values: \[ \text{pH} = \frac{1}{2} \left( 14 + 4.74 - 2 \right) = \frac{1}{2} \left( 16.74 \right) = 8.37 \] ### Step 5: Select the Best Indicator Now, we need to determine which indicator has a pH transition range that includes 8.37: 1. **Bromothymol blue**: pH range 6.0 - 7.6 (not suitable) 2. **Thymolphthalein**: pH range 9.3 - 10.5 (not suitable) 3. **Malachite green**: pH range 11.4 - 13 (not suitable) 4. **M-Cresol purple**: pH range 7.4 - 9.0 (suitable) Since 8.37 falls within the range of M-Cresol purple, it is the best indicator for this titration. ### Conclusion The best indicator for the titration of 20 mL of 0.02 M CH₃COOH with 0.02 M NaOH is **M-Cresol purple**. ---
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