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What is the minimum pH required to preve...

What is the minimum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M `ZnCl_(2)` and saturated with 0.10 M `H_(2)S` ?
`["Given" :K_(sp)=10^(-21),K_(a_1)xxK_(a_2)=10^(-20)]`

A

0

B

1

C

2

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To determine the minimum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M ZnCl₂ and saturated with 0.10 M H₂S, we can follow these steps: ### Step 1: Understand the Dissociation of H₂S H₂S dissociates in two steps: 1. H₂S ⇌ H⁺ + HS⁻ (with equilibrium constant K₁) 2. HS⁻ ⇌ H⁺ + S²⁻ (with equilibrium constant K₂) The product of these two dissociation constants is given as: \[ K_a1 \times K_a2 = 10^{-20} \] ### Step 2: Write the Solubility Product Expression for ZnS The solubility product (Ksp) for ZnS is given by: \[ K_{sp} = [Zn^{2+}][S^{2-}] \] Where: - [Zn²⁺] is the concentration of zinc ions, which comes from the dissociation of ZnCl₂. - [S²⁻] is the concentration of sulfide ions. ### Step 3: Calculate the Concentration of Zn²⁺ From the dissociation of ZnCl₂: \[ ZnCl₂ \rightarrow Zn^{2+} + 2Cl^{-} \] Since the concentration of ZnCl₂ is 0.01 M, the concentration of Zn²⁺ is also: \[ [Zn^{2+}] = 0.01 \, M \] ### Step 4: Relate [S²⁻] to Ksp Using the Ksp value for ZnS: \[ K_{sp} = [Zn^{2+}][S^{2-}] = 10^{-21} \] Substituting the known concentration of Zn²⁺: \[ 10^{-21} = (0.01)[S^{2-}] \] From this, we can solve for [S²⁻]: \[ [S^{2-}] = \frac{10^{-21}}{0.01} = 10^{-19} \, M \] ### Step 5: Use the Relationship Between [H⁺], [HS⁻], and [S²⁻] From the earlier step, we know: \[ K_a1 \times K_a2 = \frac{[H^+]^2 [S^{2-}]}{[H_2S]} \] Substituting the known values: \[ 10^{-20} = \frac{[H^+]^2 (10^{-19})}{0.1} \] ### Step 6: Solve for [H⁺] Rearranging the equation gives: \[ [H^+]^2 = 10^{-20} \times 0.1 \times 10^{19} \] \[ [H^+]^2 = 10^{-21} \] Taking the square root: \[ [H^+] = 10^{-10.5} \] ### Step 7: Calculate the pH The pH is calculated using the formula: \[ pH = -\log[H^+] \] Substituting the value: \[ pH = -\log(10^{-1}) = 1 \] ### Conclusion The minimum pH required to prevent the precipitation of ZnS is: \[ \text{Minimum pH} = 1 \]
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