If the enthalpy of formation and enthalpy of solution of HCl (g) are -92.3kJ /mol and -75.14kJ/mol respectively then find the enthalpy of `Cl^(-)`(aq):

Options

A. `-17.16` kJ/mol
B. `-167.44` kJ/mol
C. 17.16 kJ/mol
D. None of these

Answer

B

Explanation

`HCl(g)+aqrarrH^(+)(aq.)+Cl^(-)(aq.),`
`Delta_(r )H=-75.14`
`-75.14 = Delta_(f)H(H^(+),aq)+Delta_(f)H(Cl^(-),g)-Delta_(f)H(HCl, g)`
`because " "Delta_(f)H(H^(+),aq)=0`
`Delta_(f)H(Cl^(-),aq)=-75.14-92.3`
`=-167.44 " kJ"//"mol"`