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The first law of thermodynamics for a cl...

The first law of thermodynamics for a closed system is dU = dq + dw, where dw = `dw_(pv)+dw_("non-pv")`. The most common type of `w_("non-pv")` is electrical work. As per IUPAC convention work done on the system is positive.
A system generates 50 J of electrical energy and delivers 150 J of pressure-volume work against the surroundings while releasing 300 J of heat energy. What is the change in the internal energy of the system?

A

`-100`

B

`-400`

C

`-300`

D

`-500`

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The correct Answer is:
To solve the problem using the first law of thermodynamics, we need to analyze the given information step by step. ### Step 1: Understand the first law of thermodynamics The first law of thermodynamics states that the change in internal energy (dU) of a closed system is equal to the heat added to the system (dq) plus the work done on the system (dw): \[ dU = dq + dw \] ### Step 2: Identify the values given in the problem - Electrical energy generated by the system: **50 J** (this is work done by the system, so it will be treated as negative when calculating dU) - Pressure-volume work done by the system: **150 J** (this is also work done by the system, so it will be treated as negative) - Heat released by the system: **300 J** (since heat is released, it will be treated as negative) ### Step 3: Assign the values to dq and dw - Since the system releases heat, we have: \[ dq = -300 \, \text{J} \] - The total work done (dw) is the sum of pressure-volume work and electrical work: \[ dw = -150 \, \text{J} \, (\text{pressure-volume work}) - 50 \, \text{J} \, (\text{electrical work}) \] \[ dw = -150 - 50 = -200 \, \text{J} \] ### Step 4: Substitute dq and dw into the first law equation Now, substitute the values of dq and dw into the first law equation: \[ dU = dq + dw \] \[ dU = (-300 \, \text{J}) + (-200 \, \text{J}) \] ### Step 5: Calculate the change in internal energy Now, perform the calculation: \[ dU = -300 - 200 = -500 \, \text{J} \] ### Final Answer The change in the internal energy of the system is: \[ \boxed{-500 \, \text{J}} \] ---

To solve the problem using the first law of thermodynamics, we need to analyze the given information step by step. ### Step 1: Understand the first law of thermodynamics The first law of thermodynamics states that the change in internal energy (dU) of a closed system is equal to the heat added to the system (dq) plus the work done on the system (dw): \[ dU = dq + dw \] ### Step 2: Identify the values given in the problem - Electrical energy generated by the system: **50 J** (this is work done by the system, so it will be treated as negative when calculating dU) ...
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NARENDRA AWASTHI ENGLISH-THERMODYNAMICS-Level 3
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