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5 mole of an ideal gas at temp. T are co...

5 mole of an ideal gas at temp. T are compressed isothermally from 12 atm. To 24 atm. Calculate the value of 10 r. Where, `r=("Work done along reversible process")/("Work done along single step irreversible process")" (Given : ln 2 = 0.7)"`

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To solve the problem, we need to calculate the value of \(10R\), where \(R\) is defined as the ratio of the work done along a reversible process to the work done along a single-step irreversible process. We will follow these steps: ### Step 1: Identify the Given Information - Number of moles, \(n = 5\) moles - Initial pressure, \(P_1 = 12\) atm - Final pressure, \(P_2 = 24\) atm - Temperature, \(T\) (constant during isothermal process) - Given: \(\ln 2 = 0.7\) ### Step 2: Calculate Work Done in Reversible Process The work done during an isothermal reversible process can be calculated using the formula: \[ W_{\text{rev}} = -nRT \ln \left(\frac{P_1}{P_2}\right) \] Substituting the values we have: \[ W_{\text{rev}} = -5RT \ln \left(\frac{12}{24}\right) = -5RT \ln \left(\frac{1}{2}\right) = -5RT (-\ln 2) = 5RT \ln 2 \] Using the given value of \(\ln 2 = 0.7\): \[ W_{\text{rev}} = 5RT \times 0.7 = 3.5RT \] ### Step 3: Calculate Work Done in Irreversible Process The work done during a single-step irreversible process can be calculated using the formula: \[ W_{\text{irrev}} = -P_{\text{ext}} \Delta V \] For isothermal processes, we can express \(\Delta V\) in terms of pressures: \[ \Delta V = \frac{nRT}{P_1} - \frac{nRT}{P_2} \] Thus, we can write: \[ W_{\text{irrev}} = -P_{\text{ext}} \left(\frac{nRT}{P_2} - \frac{nRT}{P_1}\right) \] Here, we take \(P_{\text{ext}} = P_2 = 24\) atm: \[ W_{\text{irrev}} = -24 \left(\frac{5RT}{24} - \frac{5RT}{12}\right) \] Calculating the difference: \[ \frac{5RT}{24} - \frac{5RT}{12} = \frac{5RT}{24} - \frac{10RT}{24} = -\frac{5RT}{24} \] Thus: \[ W_{\text{irrev}} = -24 \left(-\frac{5RT}{24}\right) = 5RT \] ### Step 4: Calculate \(R\) Now we can find \(R\): \[ R = \frac{W_{\text{rev}}}{W_{\text{irrev}}} = \frac{3.5RT}{5RT} = \frac{3.5}{5} = 0.7 \] ### Step 5: Calculate \(10R\) Finally, we calculate \(10R\): \[ 10R = 10 \times 0.7 = 7 \] ### Final Answer Thus, the value of \(10R\) is: \[ \boxed{7} \]
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