Which of the following can be must readily liquefied? The given value of `a` for `NH_(3)` is `4.17`, `CO_(2)` is `3.59`, `SO_(2)` is `6.71`, and `Cl_(2)` is `6.49`.

Options

A. `NH_(3)`
B. `Cl_(2)`
C. `SO_(2)`
D. `CO_(2)`

Explanation

To determine which gas can be most readily liquefied, we need to analyze the provided values of the van der Waals constant 'a' for each gas. The van der Waals constant 'a' is a measure of the attractive forces between particles in a gas. A higher value of 'a' indicates stronger intermolecular forces, which means the gas can be more easily liquefied.

**Step-by-step solution:**

1. **Identify the given values of 'a':**
- For NH₃ (Ammonia), a = 4.17
- For CO₂ (Carbon Dioxide), a = 3.59
- For SO₂ (Sulfur Dioxide), a = 6.71
- For Cl₂ (Chlorine), a = 6.49

2. **Compare the values of 'a':**
- NH₃: 4.17
- CO₂: 3.59
- SO₂: 6.71
- Cl₂: 6.49

3. **Determine the highest value of 'a':**
- The highest value among the given constants is for SO₂, which is 6.71.

4. **Conclusion:**
- Since SO₂ has the highest value of 'a', it indicates that it has the strongest intermolecular forces among the given gases. Therefore, SO₂ can be most readily liquefied.

**Final Answer: SO₂ (Sulfur Dioxide)**

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