For two samples of ideal gases A and B curves are plotted n vs V (volume of container ) at 16.42 atm pressure. Then temperature of A and B respectively are:
(a)`(200)/(sqrt(3))K,200sqrt(3) K`
(b)`(200)/(sqrt(3))@_(C),(200sqrt(3))^(@)C`
(c)`200sqrt(3)K,(200)/(sqrt(3))K`
(d)`200K,(sqrt(3))/(200)K`

Options

A. `(200)/(sqrt(3))K,200sqrt(3) K`
B. `(200)/(sqrt(3))@_(C),(200sqrt(3))^(@)C`
C. `200sqrt(3)K,(200)/(sqrt(3))K`
D. `200K,(sqrt(3))/(200)K`

Answer

a

Explanation

(a) `n=((P)/(RT))V`
Slope of line `=(P)/(RT)=tantheta`
`implies" "T=(P)/(Rtantheta)=(16.42)/(0.0821tantheta)`
For B, `T=200sqrt(3)K`
For A, `T=(200)/(sqrt(3))K`