If a parabola has the origin as its focus and the line x = 2 as the directrix, then the coordinates of the vertex of the parabola are

If the focus is (1,-1) and the directrix is the line x+2y-9=0, the vertex of the parabola is

Find the coordinates of the vertex and the focus of the parabola y^(2)=4(x+y) .

If the focus of a parabola is (2, 3) and its latus rectum is 8, then find the locus of the vertex of the parabola.

If the focus of a parabola is (2, 3) and its latus rectum is 8, then find the locus of the vertex of the parabola.

If the bisector of angle A P B , where P Aa n dP B are the tangents to the parabola y^2=4a x , is equally, inclined to the coordinate axes, then the point P lies on the tangent at vertex of the parabola directrix of the parabola circle with center at the origin and radius a the line of the latus rectum.

Find the equation of parabola whose focus is (0,1) and the directrix is x+2=0. Also find the vertex of the parabola.

Find the vertex, focus, directrix and length of the latus rectum of the parabola y^2 - 4y-2x-8=0

Find the coordinates of the focus, axis, the equation of the directrix and latus rectum of the parabola y^2=8x .

Consider a circle with its centre lying on the focus of the parabola, y^2=2px such that it touches the directrix of the parabola. Then a point of intersection of the circle & the parabola is:

The equation of a normal to the parabola y=x^(2)-6x+6 which is perpendicular to the line joining the origin to the vertex of the parabola is