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Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 ...

Let the line `(x-2)/3=(y-1)/(-5)=(z+2)/2` lie in the plane `x""+""3y""-alphaz""+beta=""0` . Then `(alpha,beta)` equals (1) `(6,""""-17)` (2) `(-6,""7)` (3) `(5,"" -15)` (4) `(-5,""5)`

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To solve the problem step by step, we will analyze the given line and plane and find the values of \( \alpha \) and \( \beta \). ### Step 1: Identify the line and its direction ratios The line is given by the equation: \[ \frac{x - 2}{3} = \frac{y - 1}{-5} = \frac{z + 2}{2} \] From this, we can extract the direction ratios of the line: ...
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