`y^2+4(x−a^2)=0`. One of the vertexes of `Delta'(Delta)` is a vertex of the given parabola and other two vertices are the points where parabola meets their axis. If area of triangle is 250.Then a will be (A) `5` (B) `5sqrt3` (C) `25sqrt3` (D)`3sqrt5`

If an equilateral Delta is inscribed in a parabola y^(2) = 12x with one of the vertex is at the vertex of the parabola then its height is

If the area of the triangle whose one vertex is at the vertex of the parabola, y^(2) + 4 (x - a^(2)) = 0 and the other two vertices are the points of intersection of the parabola and Y-axis, is 250 sq units, then a value of 'a' is

If chord BC subtends right angle at the vertex A of the parabola y^(2)=4x with AB=sqrt(5) then find the area of triangle ABC.

An equilateral triangle is inscribed in the parabola y^(2) = 8x with one of its vertices is the vertex of the parabola. Then, the length or the side or that triangle is

An equilateral triangle is inscribed in the parabola y^(2)=4ax whose vertex is at the vertex of the parabola .Find the length of its side.

find the third vertex of triangle whose centroid is origin and two vertices are (2,4,6) and (0,-2,5)

An equilateral triangle is inscribed in the parabola y^2=4ax whose vertex is at of the parabola. Find the length of its side.

Consider a branch of the hypebola x^2-2y^2-2sqrt2x-4sqrt2y-6=0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is (A) 1-sqrt(2/3) (B) sqrt(3/2) -1 (C) 1+sqrt(2/3) (D) sqrt(3/2)+1

The length of the side of an equilateral triangle inscribed in the parabola, y^2=4x so that one of its angular point is at the vertex is:

The vertex of the right angle of a right angled triangle lies on the straight line 2x +y- 10 =0 and the two other vertices, at points (2,-3) and (4,1) then the area of triangle in sq. units is-