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The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the secon of these terms, the three terms now form an A.P. . Then the sum of the original three terms of the given G.P. is

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The product of three consecutive terms of a GP is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an AP. Then the sum of the original three terms of the given GP is: (a) 36 (b) 32 (c) 24 (d) 28

The product of first three terms of a G.P. is 1000 . If we add 6 to its second term and 7 to its third term, the resulting three terms form an A.P. Find the terms of the G.P.

The product of three consecutive terms of a GP Is -64 and the first term is four times the third. Find the terms.

The sum of three consecutive terms of an A.P. is 21 and the sum of their squares is 165. Find these terms.

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.

The product of three consecutive terms of a G.P. is 64. The sum of product of numbers taken in pair is 56. Find the numbers.

The product of first three terms of a G.P. is 1000. If 6 added to its second term and 7 added to its third term, the terms become in A.P. Find the G.P.

The sum of the first three terms of G.P. is 7 and the sum of their squares is 21. Determine the first five terms of the G:P.

The sum of three consecutive terms of an AP is 15 and their product is 105, find numbers.

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