Given `ABCD` is a parallelogram with vertices as `A(1,2),B(3,4)` and `C(2,3)`. Then the equation of line `AD` is (A) `x+y+1=0` (B) `x-y+1=0` (C) `-x+y+1=0` (D) `x+y-1=0`

Let ABC is a triangle whose vertices are A(1, –1), B(0, 2), C(x', y') and area of triangleABC is 5 and C(x', y') lie on 3x + y – 4lambda = 0 , then

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x - y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x + y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

The equation of tangent to hyperbola 4x^2-5y^2=20 which is parallel to x-y=2 is (a) x-y+3=0 (b) x-y+1=0 (c) x-y=0 (d) x-y-3=0

Equation of the bisector of angle B of the triangle ABC is y = x . If A is (2,6) and B is (1, 1) ; equation of side BC is (A) 2x + y - 3 = 0 (B) x-5y+ 4 =0 (C) x- 6y + 5 = 0 (D) none of these

The following line(s) is (are) tangent to the curve y=x^2 - x (A) x-y=0 (B) x+y=0 (C) x-y=1 (D) x+y=1

If the volume of tetrahedron A B C D is 1 cubic units, where A(0,1,2),B(-1,2,1) and C(1,2,1), then the locus of point D is a. x+y-z=3 b. y+z=6 c. y+z=0 d. y+z=-3

The equation of the incircle of the triangle formed by the coordinate axes and the line 4x + 3y - 6 = 0 is (A) x^(2) + y^(2) - 6x - 6y - 9 = 0 (B) 4 (x^(2) + y^(2) - x - y) + 1 = 0 (C) 4 (x^(2) + y^(2) + x + y) + 1 = 0 (D) 4 (x^(2) + y^(2) - x - y ) - 1 = 0

The image of line 2x+y=1 in line x+y+2=0 is : (A) x+2y-7=0 (B) 2x+y-7=0 (C) x+2y+7=0 (D) 2x+y+7=0

The matrix [(0,1),(1,0)] is the matrix of reflection in the line (A) x-y=0 (B) x+y=0 (C) x-y=1 (D) x+y=1