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Let sin(alpha -beta) = (5)/(13) and cos...

Let `sin(alpha -beta) = (5)/(13)` and `cos(alpha + beta) = (3)/(5)`, then `tan(2alpha)` is equal to (Here `alpha, beta in (0, (pi)/(4)))` (A) `(63)/(16)` (B) `(61)/(16)` (C) `(65)/(16)` (D) `(32)/(9)`

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